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denis-greek [22]
3 years ago
10

Which polynomials are in standard form?

Mathematics
2 answers:
Romashka [77]3 years ago
5 0

Answer:

6,4,3

Step-by-step explanation:

Mice21 [21]3 years ago
4 0

Answer:

options 2, 4 and 6

Step-by-step explanation:

standard form means there are no fraction coefficients, that they are ordered from greatest exponent to smallest, and by the letters of alphabet

1)

x^2*y^3+y^1+3x^1*y^2

should be x^2*y^3+3x^1*y^2+y^1

2) in standard form

3)

4x*y+2x^2*y^2+x*y^3

should be 2x^2*y^2+x*y^3+4x*y (if there are same exponents of x, put in order of decreasing y coefficients)

4) in standard form

5)

14b^3+a^1*b^3-6a^1*b^1+8a^1*b^2

should be a^1*b^3+8a^1*b^2-6a^1*b^1+a^0*14b^3 (14b^3 is last, since descending a exponents are the priority, and it has a^0 while rest have a^1)

6) in standard form

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A coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4x).

The 2 and + are out since they don't have variables(and the + is just a +).

So 4 and x are left. x is a variable, not a coefficient, so the last(and correct) answer is 4.

---

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