Answer: (g-f)(x)=-4x
Explanation: According to the graph, line created by function f(x) passes through the points (1,-3) and (0,0) and similarly, line created by the function passes through the points (1,1) and (0,0).
Thus, we can find the equation of the lines with help of formula
× 
so, equation of line created by function f(x)
y+3=
×(x-1)
y+3=
×(x-1)
y+3=-3x+3
y=-3x thus function f(x)=-3x
similarly, equation of line created by function g(x)
y=x thus function g(x)=x
Now, we have to find out, (g-f) (x)= g(x)-f(x)= -3x-x= -4x
The value of n is 11.
<u>Step-by-step explanation</u>:
The given expression is (n-9) ÷ 10 = -2
<u>To find the value of n</u> :
- From the expression, it is determined that (n-9) is the numerator and 10 is the denominator.
- Cross multiply the denominator in the left side of the expression to the another side.
The expression becomes (n-9) = (10
-2).
⇒ n-9 = -20
Keep the n term on one side and the constants on other side.
⇒ n = -20+9
⇒ n = -11
Therefore, the value of n is 11.
To calculate the relative vector of B we have to:
![P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]](https://tex.z-dn.net/?f=P_B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C3%5C%5C-2%5C%5C3%2F2%5Cend%7Barray%7D%5Cright%5D)
The coordenates of:
, with respect to B satisfy:

Equating coefficients of like powers of t produces the system of equation:

After solving this system, we have to:

And the result is:
![P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]](https://tex.z-dn.net/?f=P_B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C3%5C%5C-2%5C%5C3%2F2%5Cend%7Barray%7D%5Cright%5D)
Learn more: brainly.com/question/16850761
Answer:
a, b, c, & d
Step-by-step explanation: