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blsea [12.9K]
3 years ago
7

How would you write 0.5 Repeating as a fraction

Mathematics
2 answers:
amm18123 years ago
8 0

Answer:

59

Step-by-step explanation:

Since this fraction repeats the same number it must have a denominator of 9 and a numerator of the repeating digit the repeating digit is 5 so the fraction is 59

PilotLPTM [1.2K]3 years ago
6 0

Let <em>x</em> = 0.555…

Then 10<em>x</em> = 5.555…

Subtract one from the other to get

10<em>x</em> - <em>x</em> = 5.555… - 0.555…

Notice how the fractional parts on the right cancel. This leaves you with

9<em>x</em> = 5

and so

<em>x</em> = 5/9

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The thickness of each type of coin is shown in the table. How much thicker is stack of dollars worth of nickels than a dollars w
Lilit [14]
Let our basis be worth 1 dollar. A nickel's worth is $0.05. In order to come up with $1, the number of nickels should be:

Number of nickels = $1 * 1 nickel/$0.05 = 20 nickels
Thickness of 20 nickels = 20 nickels * 1.95 mm = 39 mm

Let's do the same for the quarters. Each quarter is worth $0.25.

Number of quarters = $1 * 1 quarter/$0.25 = 4 quarters
Thickness of 4 quarters = 4 quarters * 1.75 mm = 7 mm

Find the ratio of the two:
39 mm/7 mm = 5.57

Therefore, a stack of nickels is 5.57 times thicker than a stack of quarters worth one dollar.
7 0
4 years ago
Find 3 consecutive integets such that the sum of the first two integers is 24 more than the third. ​
Elina [12.6K]

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4 years ago
Consider the quadratic function f(x)=−x^2+x+30
yaroslaw [1]

Answer:

The smallest xx-intercept is x = -5

The largest xx-intercept is x = 6

The yy-intercept is y = 30.

Step-by-step explanation:

Given a quadratic function in the following format:

f(x) = ax^{2} + bx + c = 0, a \neq 0

The x-values of the x-intercepts are x_{1}, x_{2}, given by the following formulas.

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

We have that:

f(x) = -x^{2} + x + 30

This is not in the format above. I will multiply by (-1), so we have:

f(x) = x^{2} - x - 30

So, a = 1, b = -1, c = -30

\bigtriangleup = b^{2} - 4ac = (-1)^{2} - 4*(1)*(-30) = 1 + 120 = 121

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) + \sqrt{121}}{2(1)} = \frac{12}{2} = 6

x_{2} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) - \sqrt{121}}{2(1)} = \frac{-10}{2} = -5

This means that

The smallest xx-intercept is x = -5

The largest xx-intercept is x = 6

The y-intercept is the value of f(x) when x = 0. So

f(x)=−x^{2}+x+30

f(0) = 30

The yy-intercept is y = 30.

5 0
3 years ago
Which relation is a function?
Dmitrij [34]

Answer:

{(a, 1),(b, 1),(c, 1)}

Step-by-step explanation:

Each x-value needs to have only one y-value in order to be a function

3 0
3 years ago
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lesya692 [45]
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