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levacccp [35]
2 years ago
8

Cindy received a bank statement reporting the recent changes to her

Mathematics
2 answers:
krek1111 [17]2 years ago
6 0

Answer:

1218.58

Step-by-step explanation:

lubasha [3.4K]2 years ago
6 0
It’s 1218.58 hope this helps
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What are the slopes ?
Viefleur [7K]

Answer:

11. is a slope of -7/2

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Step-by-step explanation:

7 0
3 years ago
During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for
AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is :  \hat p = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

      P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion = 0.345

           n = sample of participants = 3532

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population​ proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                         significance are -1.96 & 1.96}

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u>= [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

    = [ 0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } , 0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } } ]

    = [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

6 0
3 years ago
Graph the line with slope -3 passing through the point (5,1) .
hichkok12 [17]

Answer:

we know that,

y-y1=m(x-x1)

or, y-1=-3(x-5)

or, y-1=15-3x

or 3x+y-16=0 is the required equation

3 0
3 years ago
I need help on Dividing Fractions?
vlabodo [156]

You have to write the problem you need help with.
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3 years ago
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Need answer ASAP<br><br><br><br><br> Express a 10/3 b 7/3 in simplified radical form.
anastassius [24]
I guess this is what you mean     3√a^10      and 3√b^7
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3 years ago
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