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MArishka [77]
3 years ago
7

Solve the equation using square roots. (X+3)^2=0

Mathematics
1 answer:
Vilka [71]3 years ago
7 0

Answer:

x=3

Step-by-step explanation:

(x−3)^2=0

Set the x−3 equal to 0.

x−3=0

Add 3 to both sides of the equation.

x=3

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X/3-1/2=3/4<br> contains fractions
Elenna [48]

Answer:

x= 15/4

Step-by-step explanation:

Starting Equation

(x/3) - (1/2) = 3/4

Add 1/2 by both sides

(x/3) = 3/4 + 1/2

Find the common denominator (4)

(x/3) = 3/4 + 2/4

Add

(x/3) = 5/4

Multiply 3 by both sides to get x by itself

x = 15/4

4 0
3 years ago
Read 2 more answers
How many solutions does the equation 2p + 9 = 5 + 4 + 2p have?
spayn [35]

Answer:

infinite solution

Step-by-step explanation:

the y intercept and the slope are the same

8 0
3 years ago
As a rule of thumb, the sampling distribution of the sample proportion can be approximated by a normal probability distribution
netineya [11]

As a rule of thumb, when each component is selected independently from the same population, the sampling distribution of the sample percentage may be estimated by a regular probability distribution.

<h2>Why is it crucial to use the thumb rule?</h2>
  • One of our primary, simple-to-learn ways to handle complexity is the rule of thumb. Real thumb rules take into account operating, security, and financial constraints.
  • They inform us of the likely location of a practical solution. Additionally, they reveal which tactics are most prone to failure.
<h3>What is sampling distribution?</h3>
  • A statistic that is obtained by sampled data from a bigger population is known as a sampling distribution.
  • It depicts an array of potential results that may result from a statistic, such as the mean or mode of a certain parameter because there is really a population.

Therefore the main solution is- from the identical group, each component is individually chosen.

Learn more about sampling distribution here:

brainly.com/question/13501743

#SPJ4

8 0
2 years ago
A survey was conducted two years ago asking college students their top motivations for using a credit card. To determine whether
salantis [7]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- A survey was conducted among the College students for their motivations of using credit cards two years ago. A randomly selected group of sample size n = 425 college students were selected.

- The results of the survey test taken 2 years ago and recent study are as follows:

                                           

                                           Old Survey ( % )            New survey ( Frequency )

                  Reward                 27                                              112

                  Low rate               23                                              96

                  Cash back           21                                              109

                  Discount              9                                               48

                  Others                  20                                             60

- We are to test the claim for any changes in the expected distribution.

We will state the hypothesis accordingly:

Null hypothesis: The expected distribution obtained 2 years ago for the motivation behind the use of credit cards are as follows: Rewards = 27% , Low rate = 23%, Cash back = 21%, Discount = 9%, Others = 20%

Alternate Hypothesis: Any changes observed in the expected distribution of proportion of reasons for the use of credit cards by college students.

( We are to test this claim - Ha )

We apply the chi-square test for independence.

- A chi-square test for independence compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each other.

- We will compute the chi-square test statistics ( X^2 ) according to the following formula:

 

                                X^2 = Sum [ \frac{(O_i - E_i)^2}{Ei} ]

Where,

 O_i : The observed value for ith data point

 E_i : The expected value for ith data point.

- We have 5 data points.

So, Oi :Rewards = 27% , Low rate = 23%, Cash back = 21%, Discount = 9%, Others = 20% from a group of n = 425.

     Ei : Rewards = 112 , Low rate = 96, Cash back = 109, Discount = 48, Others = 60.

Therefore,

                               

                     X^2 = [ \frac{(112 - 425*0.27)^2}{425*0.27} +  \frac{(96 - 425*0.23)^2}{425*0.23} +  \frac{(109 - 425*0.21)^2}{425*0.21} +  \frac{(48 - 425*0.09)^2}{425*0.09} +  \frac{(60 - 425*0.20)^2}{425*0.20}]\\\\X^2 = [ 0.06590 + 0.03132 + 4.37044 +  2.48529 +  7.35294]\\\\X^2 = 14.30589

- Then we determine the chi-square critical value ( X^2- critical ). The two parameters for evaluating the X^2- critical are:

                     Significance Level ( α ) = 0.10

                     Degree of freedom ( v ) = Data points - 1 = 5 - 1 = 4  

Therefore,

                     X^2-critical = X^2_α,v = X^2_0.1,4

                    X^2-critical = 7.779

- We see that X^2 test value = 14.30589 is greater than the X^2-critical value = 7.779. The test statistics value lies in the rejection region. Hence, the Null hypothesis is rejected.

Conclusion:-

This provides us enough evidence to conclude that there as been a change in the claimed/expected distribution of the motivations of college students to use credit cards.

6 0
4 years ago
Put the following equation of a line into slope-intercept form, simplifying all fractions.
Elena L [17]

Answer:

<h2>y=(-8)-2x</h2>

<em>2x-2y=(-10)</em>

<em>-2x        -2x</em>

-2y=(-10)-2x

+2      +2

y=(-8)-2x

<em />

<em />

3 0
3 years ago
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