A(1) = 2
a(2) = 4
You can see that the terms are increasing by +2.
so
a(1) = 2
a(2) = 4
a(3) = 6
a(4) = 8
a(5) = 10
a(6) = 12
a(7) = 14
a(8) = 16
a(9) = 18
a(10) = 20
your answer is a(10) = 20.
Speed = Distance / Time
Distance = 5t^4 - 10t^2+6
Time = t+2
Now:
5t^4 - 10t^2 + 6 | t+2
-5t^4 -10t^3 5t^3 - 10t^2 + 10t - 20
\\\\\ -10t^3-10t^2+6
+10t^3+20t^2
\\\\\\\ 10t^2+6
-10t^2-20t
\\\\\ -20t+6
+20t+40
\\\\\ 46
<span>C. 5t^3-10t^2+10t-20+(46)/(t+2))</span>