What is the focus of the parabola given by the equation y = x2 − 2x − 3?
y = x2 − 2x − 3
y = x2 − 2x − 3 -1 +1y = (x - 1)^2 - 4 h = 1 and k = - 4 and a = 1
Vertex (a, k) so it is (1,-4)
Now focus is
(1, -4 + 1/4) = (1,-3 3/4)
or
(1,-3.75)
Answer:
We kindly invite you to see the image attached for further details.
Step-by-step explanation:
From Analytical Geometry we get that linear functions can be found after knowing a point and its slope. The standard form of a linear function is represented by the following formula:
(Eq. 1)
Where:
- Independent variable, dimensionless.
- Dependent variable, dimensionless.
- Slope, dimensionless.
- y-Intercept, dimensionless.
At first we need to calculate the y-Intercept, which is cleared within (Eq. 1):
If we know that 
, 
and 
, then the y-Intercept of the linear function is:
Line with a slope of 
that goes through the point (2, 1) is represented by 
.
Lastly, we graph the line by using a plotting software (i.e. Desmos), whose result is included below as attachment.
See the attached file. I hope I was of help.
I thought it was eight bro;;-;
Answer:
Describe the possible outcomes.
Link each outcome to one or more random numbers.
Choose a source of random numbers.
Choose a random number.
Based on the random number, note the "simulated" outcome.
Repeat steps 4 and 5 multiple times; preferably, until the outcomes show a stable pattern.
Step-by-step explanation: i honestly don't know i got this off of the gooooogle :D
