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RUDIKE [14]
3 years ago
6

A bus has 15 passengers. At the first stop, 5 passengers board the bus and 2 passengers get off the bus. At the second stop, 3 p

assengers board the bus and some passengers get off the bus.
15 passengers are still on the bus.

How many passengers got off the bus at the second stop?
Mathematics
1 answer:
andrezito [222]3 years ago
8 0
Stop 1 : -

15 + 5 = 20

20 - 2 = 18

So, on the first stop 18 passengers were left on the bus going to the next stop.

Stop 2 : - 

18 + 3 = 21

21 - 15 = 6

So, 6 passengers get off at the 2nd stop.

Hope I helped ya!! 


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Pls help me I am confused
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Answer:

\huge\boxed{A.\ \dfrac{565}{182}}

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<u>1)  -33 × 1 = -33   ⇒   Sum is:   -33 + 1 = -32</u>

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3)  -3 × 11 = -33   ⇒   Sum is:   -3 + 11 = 8

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<u>5)  1 × (-33) = -33   ⇒   Sum is:   1 + (-33) = 1 - 33 = -32</u>

6)  3 × (-11) = -33   ⇒   Sum is:   3 + (-11) = 3 - 11 = -8

7)  11 × (-3) = -33   ⇒   Sum is:   11 + (-3) = 11 - 3 = 8

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<h2>The least possible sum of a and b is  -32</h2>

to 1)  and to 5)



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