A rectangular lot is 75 yards wide and 120 yards long. Give the length and width of another rectangular lot that has the same pe
rimeter but a larger area.
1 answer:
Answer:
119 yds and 76 yds
Step-by-step explanation:
area of 1st rect = 9000 yd^2
perimeter = 2(75+120)= 2*195=390
perimeter of 2nd rectangle = 390
l+b = 390/2= 195
the minimum l of 2nd rectangle = 119
min b of 2nd rectangle = 76
119*76 =9044
You might be interested in
The incorrect one is 35 × 10⁵
it can be written as :
Answer:
no
Step-by-step explanation:
Answer:
y=2x-5
Step-by-step explanation:
Answer:
twenty-six thousandths in decimal form is "0.0026"
Hope this helped
Step-by-step explanation:
Answer:
bbehejriswkkrjdjajwjejjduds9s
