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Novosadov [1.4K]
3 years ago
10

1. write it on a piece of paper

Mathematics
2 answers:
stiv31 [10]3 years ago
7 0

\\ \sf\longmapsto 1\dfrac{1}{2}+2\dfrac{3}{4}

\\ \sf\longmapsto \dfrac{3}{2}+\dfrac{11}{4}

\\ \sf\longmapsto \dfrac{6+11}{4}

\\ \sf\longmapsto \dfrac{17}{4}

2:-

\\ \sf\longmapsto 4\dfrac{3}{7}+6\dfrac{1}{5}

\\ \sf\longmapsto \dfrac{31}{7}+\dfrac{31}{5}

\\ \sf\longmapsto \dfrac{155+225}{35}

\\ \sf\longmapsto \dfrac{380}{35}

\\ \sf\longmapsto 12

3:-

\\ \sf\longmapsto 4\dfrac{2}{5}+5\dfrac{2}{6}

\\ \sf\longmapsto \dfrac{22}{5}+\dfrac{32}{6}

\\ \sf\longmapsto \dfrac{132+160}{30}

\\ \sf\longmapsto \dfrac{292}{30}

4:-

\\ \sf\longmapsto 3\dfrac{7}{7}+3\dfrac{1}{3}

\\ \sf\longmapsto \dfrac{28}{7}+\dfrac{10}{3}

\\ \sf\longmapsto 4+\dfrac{10}{3}

\\ \sf\longmapsto \dfrac{12+10}{3}

\\ \sf\longmapsto \dfrac{22}{3}

erastovalidia [21]3 years ago
6 0
<h2>1.</h2>

\bf \large \longrightarrow \:  \: 1 \frac{1}{2}  \:  +  \: 2 \frac{3}{4}  \:  =  \:  \\

\bf \large \longrightarrow \:  \:  \frac{3}{2}  \:  +  \:  \frac{11}{4}  \\

\bf \large \longrightarrow \:  \:  \frac{6 \:  +  \:11 }{4}  \\

\bf \large \longrightarrow \:  \:  \frac{17}{4}  \\

<h2>2.</h2>

\bf \large \longrightarrow \:  \: 4 \frac{3}{7}  \:  +  \: 6 \frac{1}{5}  \\

\bf \large \longrightarrow \:  \:  \frac{31}{7}   \:  +  \:  \frac{31}{5}  \\

\bf \large \longrightarrow \:  \:  \frac{155 \:  +  \: 217}{35}   \\

\bf \large \longrightarrow \:  \:  \frac{372}{35}  \\

<h2>3.</h2>

\bf \large \longrightarrow \:  \:  4 \frac{2}{5}  \:  +  \: 5 \frac{2}{6}  \\

\bf \large \longrightarrow \:  \: \frac{22}{5}   \:  +  \:  \frac{32}{6}  \\

\bf \large \longrightarrow \:  \:  \frac{132 \:  +  \: 160}{30}  \\

\bf \large \longrightarrow \:  \:  \frac{292}{30}  \\

<h2>4.</h2>

\bf \large \longrightarrow \:  \: 3 \frac{7}{7}  \:  +  \: 3 \frac{1}{3}  \\

\bf \large \longrightarrow \:  \:  \frac{28}{7}  \:  +  \:  \frac{10}{3} \\

\bf \large \longrightarrow \:  \:   \cancel\frac{28 ^{4} }{7 \:  ^{1} }  \:  +  \:  \frac{10}{3} \\

\bf \large \longrightarrow \:  \:  \frac{4}{1}  \:  +  \:  \frac{10}{3}  \\

\bf \large \longrightarrow \:  \:  \frac{12 \:  +  \: 10}{3}  \\

\bf \large \longrightarrow \:  \:  \frac{22}{3}  \\

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Answer:

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Angles C and D are supplementary, meaning they add up to 180 degrees. So, if we add 8u-48 to 5u+46, we get 13u-2. We set that equal to 180, so 13u-2=180. Add the two, so 13u=182. Divide the 13, so u=14. To double check, plug in 14 to both expressions. 8(14)-48 and 5(14)+46. 8(14)-48 is 64. 5(14)+46 is 116. If you add 64+116, you get 180, which proves your answer right! So u= 14

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<h2>Answer with explanation:</h2>

By considering the given information, we have

Null hypothesis : H_0: \mu=35.0

Alternative hypothesis : H_1: \mu\neq35.0

Since the alternative hypothesis is two-tailed , so the test is a two-tailed test.

Given : Sample size : n= 20, since sample size is less than 30 so the test applied is a t-test.

\overline{x}=41.0    ;    \sigma= 3.7

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

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Degree of freedom : n-1 = 20-1=19

Significance level = 0.01

For two tailed,  Significance level =\dfrac{0.01}{2}=0.005

By using the t-distribution table, the critical value of t =t_{19, 0.005}=2.861

Since , the observed t-value (7.25) is greater than the critical value (2.861) .

So we reject the null hypothesis, it means we have enough evidence to support the alternative hypothesis.

We conclude that there is some significance difference between the mean score for sober women and 35.0.

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