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Novosadov [1.4K]
3 years ago
10

1. write it on a piece of paper

Mathematics
2 answers:
stiv31 [10]3 years ago
7 0

\\ \sf\longmapsto 1\dfrac{1}{2}+2\dfrac{3}{4}

\\ \sf\longmapsto \dfrac{3}{2}+\dfrac{11}{4}

\\ \sf\longmapsto \dfrac{6+11}{4}

\\ \sf\longmapsto \dfrac{17}{4}

2:-

\\ \sf\longmapsto 4\dfrac{3}{7}+6\dfrac{1}{5}

\\ \sf\longmapsto \dfrac{31}{7}+\dfrac{31}{5}

\\ \sf\longmapsto \dfrac{155+225}{35}

\\ \sf\longmapsto \dfrac{380}{35}

\\ \sf\longmapsto 12

3:-

\\ \sf\longmapsto 4\dfrac{2}{5}+5\dfrac{2}{6}

\\ \sf\longmapsto \dfrac{22}{5}+\dfrac{32}{6}

\\ \sf\longmapsto \dfrac{132+160}{30}

\\ \sf\longmapsto \dfrac{292}{30}

4:-

\\ \sf\longmapsto 3\dfrac{7}{7}+3\dfrac{1}{3}

\\ \sf\longmapsto \dfrac{28}{7}+\dfrac{10}{3}

\\ \sf\longmapsto 4+\dfrac{10}{3}

\\ \sf\longmapsto \dfrac{12+10}{3}

\\ \sf\longmapsto \dfrac{22}{3}

erastovalidia [21]3 years ago
6 0
<h2>1.</h2>

\bf \large \longrightarrow \:  \: 1 \frac{1}{2}  \:  +  \: 2 \frac{3}{4}  \:  =  \:  \\

\bf \large \longrightarrow \:  \:  \frac{3}{2}  \:  +  \:  \frac{11}{4}  \\

\bf \large \longrightarrow \:  \:  \frac{6 \:  +  \:11 }{4}  \\

\bf \large \longrightarrow \:  \:  \frac{17}{4}  \\

<h2>2.</h2>

\bf \large \longrightarrow \:  \: 4 \frac{3}{7}  \:  +  \: 6 \frac{1}{5}  \\

\bf \large \longrightarrow \:  \:  \frac{31}{7}   \:  +  \:  \frac{31}{5}  \\

\bf \large \longrightarrow \:  \:  \frac{155 \:  +  \: 217}{35}   \\

\bf \large \longrightarrow \:  \:  \frac{372}{35}  \\

<h2>3.</h2>

\bf \large \longrightarrow \:  \:  4 \frac{2}{5}  \:  +  \: 5 \frac{2}{6}  \\

\bf \large \longrightarrow \:  \: \frac{22}{5}   \:  +  \:  \frac{32}{6}  \\

\bf \large \longrightarrow \:  \:  \frac{132 \:  +  \: 160}{30}  \\

\bf \large \longrightarrow \:  \:  \frac{292}{30}  \\

<h2>4.</h2>

\bf \large \longrightarrow \:  \: 3 \frac{7}{7}  \:  +  \: 3 \frac{1}{3}  \\

\bf \large \longrightarrow \:  \:  \frac{28}{7}  \:  +  \:  \frac{10}{3} \\

\bf \large \longrightarrow \:  \:   \cancel\frac{28 ^{4} }{7 \:  ^{1} }  \:  +  \:  \frac{10}{3} \\

\bf \large \longrightarrow \:  \:  \frac{4}{1}  \:  +  \:  \frac{10}{3}  \\

\bf \large \longrightarrow \:  \:  \frac{12 \:  +  \: 10}{3}  \\

\bf \large \longrightarrow \:  \:  \frac{22}{3}  \\

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2 years ago
Giving brainlyist to the first person to answer with a complete and correct answer.
julsineya [31]

Hi There!

Given:

  • A placemat requires 30 feet of ribbon
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How many placemats can Mandy make, if she has 200 ft of ribbon?

Solve:

200÷30≈7

Thus, she can make 7 placemats.

<h3>Hope it helps & enjoy your day!</h3>

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Which principle prevents a government from becoming too powerful?
tino4ka555 [31]

Comment: I think you got this in the wrong section but I’ll still answer it anyways.

Actual Answer: system of checks and balances

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7 0
2 years ago
Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt
Leni [432]
Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = \sqrt{Δx^2+Δy^2}
d₁ = \sqrt{(-2-1)^2+(1-4)^2}
d₂ = \sqrt{(x-1)^2+(y-4)^2}
d₁ = d₂
∴ \sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2} ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
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from equatoin (1)  y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = \pm \sqrt{9} = \pm 3
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1)  or  (-2,7)












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3 years ago
Which parent functions go through the origin? Select all that apply.
Dvinal [7]
It also goes from linear too, I don’t know what else sorry
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