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Novosadov [1.4K]
3 years ago
10

1. write it on a piece of paper

Mathematics
2 answers:
stiv31 [10]3 years ago
7 0

\\ \sf\longmapsto 1\dfrac{1}{2}+2\dfrac{3}{4}

\\ \sf\longmapsto \dfrac{3}{2}+\dfrac{11}{4}

\\ \sf\longmapsto \dfrac{6+11}{4}

\\ \sf\longmapsto \dfrac{17}{4}

2:-

\\ \sf\longmapsto 4\dfrac{3}{7}+6\dfrac{1}{5}

\\ \sf\longmapsto \dfrac{31}{7}+\dfrac{31}{5}

\\ \sf\longmapsto \dfrac{155+225}{35}

\\ \sf\longmapsto \dfrac{380}{35}

\\ \sf\longmapsto 12

3:-

\\ \sf\longmapsto 4\dfrac{2}{5}+5\dfrac{2}{6}

\\ \sf\longmapsto \dfrac{22}{5}+\dfrac{32}{6}

\\ \sf\longmapsto \dfrac{132+160}{30}

\\ \sf\longmapsto \dfrac{292}{30}

4:-

\\ \sf\longmapsto 3\dfrac{7}{7}+3\dfrac{1}{3}

\\ \sf\longmapsto \dfrac{28}{7}+\dfrac{10}{3}

\\ \sf\longmapsto 4+\dfrac{10}{3}

\\ \sf\longmapsto \dfrac{12+10}{3}

\\ \sf\longmapsto \dfrac{22}{3}

erastovalidia [21]3 years ago
6 0
<h2>1.</h2>

\bf \large \longrightarrow \:  \: 1 \frac{1}{2}  \:  +  \: 2 \frac{3}{4}  \:  =  \:  \\

\bf \large \longrightarrow \:  \:  \frac{3}{2}  \:  +  \:  \frac{11}{4}  \\

\bf \large \longrightarrow \:  \:  \frac{6 \:  +  \:11 }{4}  \\

\bf \large \longrightarrow \:  \:  \frac{17}{4}  \\

<h2>2.</h2>

\bf \large \longrightarrow \:  \: 4 \frac{3}{7}  \:  +  \: 6 \frac{1}{5}  \\

\bf \large \longrightarrow \:  \:  \frac{31}{7}   \:  +  \:  \frac{31}{5}  \\

\bf \large \longrightarrow \:  \:  \frac{155 \:  +  \: 217}{35}   \\

\bf \large \longrightarrow \:  \:  \frac{372}{35}  \\

<h2>3.</h2>

\bf \large \longrightarrow \:  \:  4 \frac{2}{5}  \:  +  \: 5 \frac{2}{6}  \\

\bf \large \longrightarrow \:  \: \frac{22}{5}   \:  +  \:  \frac{32}{6}  \\

\bf \large \longrightarrow \:  \:  \frac{132 \:  +  \: 160}{30}  \\

\bf \large \longrightarrow \:  \:  \frac{292}{30}  \\

<h2>4.</h2>

\bf \large \longrightarrow \:  \: 3 \frac{7}{7}  \:  +  \: 3 \frac{1}{3}  \\

\bf \large \longrightarrow \:  \:  \frac{28}{7}  \:  +  \:  \frac{10}{3} \\

\bf \large \longrightarrow \:  \:   \cancel\frac{28 ^{4} }{7 \:  ^{1} }  \:  +  \:  \frac{10}{3} \\

\bf \large \longrightarrow \:  \:  \frac{4}{1}  \:  +  \:  \frac{10}{3}  \\

\bf \large \longrightarrow \:  \:  \frac{12 \:  +  \: 10}{3}  \\

\bf \large \longrightarrow \:  \:  \frac{22}{3}  \\

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Answer:

The best way to know weather the formula y=x⁴-4x³+3x² is growing or not, is by graphing it.

As you can see in the attached picture:

  • For -inf<x< 0 the graph decreases.
  • For 0<x<0.634 the graph is growing
  • For 0,634<x<2.366 the graph decreases
  • For 2.366<x<+inf the graph is growing.

Therefore, the polynomial grows in the intervals stated before.

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3 years ago
(3 x 10e-4) ( 3 x 10e7)
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The answer is 9000..
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Find the slope please
zavuch27 [327]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the slope of this graph; we are provided with two points:

\star~\mathrm{(6,0)}

\star~\mathrm{(0,-5)}

\triangle~\fbox{\bf{KEY:}}

  • What we need in order to find the slope are two points and the slope formula.

Here's the formula:

\star~\boxed{\mathrm{\cfrac{y2-y1}{x2-x1}}}

Where

y2 and y1 are y-coordinates

x2 and x1 are x-coordinates

Substitute the values:

\star~\mathrm{\cfrac{-5-0}{0-6}}}

Simplify!

\star~\mathrm{\cfrac{-5}{-6}}}

Simplify more!

\star~\mathrm{\cfrac{5}{6}}

Hope it helps you out! :D

Ask in comments if any queries arise.

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4 0
2 years ago
1) Where is the midpoint of , when A (6, 7) and B (-9, -5)?
lord [1]

Answer:

(−1.5,1)

Step-by-step explanation:

Finding the distance, midpoint, slope, equation and the x y-intercepts of a line passing between the two points p1 (6,7) and p2 (-9,-5)

The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula

d = √  ((X2-X1)2+(Y2-Y1)2)

d = √ (-9-6)2+(-5-7)2

d = √ ((-15)2+(-12)2)

d = √ (225+144)

d = √ 369

The distance between the points is 19.2093727122985

The midpoint of two points is given by the formula

Midpoint= ((X1+X2)/2,(Y1+Y2)/2)

Find the x value of the midpoint

Xm=(X1+X2)/2

Xm=(6+-9)/2=-1.5

Find the Y value of the midpoint

Ym=(Y1+Y2)/2

Ym=(7+-5)/2=1

The midpoint is: (-1.5,1)

6 0
3 years ago
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Find the arc length of the partial circle.
Kay [80]

Answer:

12.42 units

Step by step explanation:

Given,

length of the radius = 2 units

Therefore, arc length of the complete circle = 2 × 3.14 × 2 units = 12.56 units

Therefore, arc length of the partial circle = 3/4 × 12.56 units

= 12.42 units

3 0
3 years ago
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