X-int:let y=0
3x-2(0)=18
3x=18
divide both sides by 3
therefore x=6
y-int:let x=0
3(0)-2y=18
-2y=18
we divide both side by -2
therefore y=-9
Answer:
#3.) The initial value of 16 gal at x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.
#4.) Find how many minutes until the barrel is empty of water.
Let y = 0, to solve for time x.
0 = (-2/5)*x + 18
(2/5)*x = 18
x = (5/2)* 18 = 5*9 = 45 minutes
Up to and after 45 minutes, the barrel is empty of water.
Step-by-step explanation:
#2.)
minutes: 5, 10, 15, 20
water(gal): 16, 14, 12, 10
Find slope: slope m = (14 - 16)/(10 - 5) = -2/5
y - 10 = (-2/5)*(x - 20)
y - 10 = (-2/5)* x + 8
y = (-2/5)*x + 18
rate of change slope means that for every minute 2/5 gallons of water is lost
#3.) The initial value of 16 gal at x = 5 minutes means that 16 gallons of water was present 5 minutes after the barrel started leaking.
#4.) Find how many minutes until the barrel is empty of water.
Let y = 0, to solve for time x.
0 = (-2/5)*x + 18
(2/5)*x = 18
x = (5/2)* 18 = 5*9 = 45 minutes
Answer:
135°
Step-by-step explanation:
seg AB=seg OB
tan ∠AOB = 1
∠AOB = 45°
∠AOC = 135°
-45x+72
you multiply the 9 by everything in the parentheses
