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disa [49]
2 years ago
13

If point H(-6, 2) is translated 4 units up and 3 units right, what are the

Mathematics
1 answer:
sesenic [268]2 years ago
5 0

Answer: H(-3 , 6)

X increase is horizontal

Y increase is vertical

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An elevator in a mine shaft is stopped at a .25 feet below ground level. And then travels 28 feet downward. What equation can be
ankoles [38]

Correct question:

An elevator in a mine shaft is stopped at 25 feet below ground level. And then travels 28 feet downward. What equation can be written to find the final position in feet of the elevator in relations to ground level?

Answer:

-53 feets

Step-by-step explanation:

Initial stop point = 25 feets below ground level

Further distance traveled = 28 feets below ground level

Final position in feet = Initial stop point + further distance traveled

Note : distances or point traveled below ground level or downward is represented as negative.

Final position in feets = (-25)feets + (-28)feets

Final position in feets = - 53 feets

3 0
2 years ago
ABCD – FECG<br> what does (x) =
Helen [10]

9514 1404 393

Answer:

  x = 12

Step-by-step explanation:

Sides of similar figures are proportional, so ...

  AB/FE = BC/EC

  x/6 = 10/5

  x = 6·(10/5) . . . multiply by 6

  x = 12

5 0
3 years ago
A bag of potato chips is packaged at sea level (1.00 atm) and has
serg [7]

Answer:

406 ml

Step-by-step explanation:

P1V1 = P2V2

(1) (.315) = (.775)(V2)

V2 = .406

3 0
2 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
2 years ago
If y=1/4 when x=5, find y when x=7, given that y directly with x
mariarad [96]

Answer:

7/20

Step-by-step explanation:

Since y varies directly with x, the ratio of y to x is proportional.

... y / 7 = (1/4)/(5)

... y / 7 = 1 / 20 . . . . simplify

... y = 7/20 . . . . . multiply by 7

3 0
3 years ago
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