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Sergio039 [100]
2 years ago
12

Best answer gets brainliest

Mathematics
1 answer:
EleoNora [17]2 years ago
4 0

Answer:

A. I believe I hope its correct I'm sorry if its wrong:( I tried.

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Thu wants to play “Guess My Number,"she states. “When I triple my number and add five ,I get twenty-six.what is my number?" What
AleksandrR [38]

The <em>correct answer</em> is:


Her number is 7.


Explanation:


Let x represent her number.


She triples her number; this is represented by 3x.


She then adds 5 to this; this gives us 3x+5.


She gets 26 aas her answer. This gives us the equation:

3x+5 = 26


To solve this, first subtract 5 from each side:


3x+5-5 = 26-5

3x = 21


Divide each side by 3:

3x/3 = 21/3

x = 7

5 0
3 years ago
Read 2 more answers
Select ALL the correct answers.
Colt1911 [192]
What are the choices for this question?
6 0
3 years ago
Charlie guesses that his dog weighs 34. 5 pounds. The dog actually weighs 32. 7 pounds. What is the percent error in Charlie’s g
expeople1 [14]

Percent error is the amount of error to actual value, in percent. The percent error in Charlie’s guess is approximately: Option D: 5.5%

<h3>How to calculate the percent error?</h3>

Suppose the actual value and the estimated values after the measurement are obtained. Then we have:

Error = Actual value - Estimated value

To calculate percent error, we will measure how much percent of actual value, the error is, in the estimated value.

\rm Percent \: Error = |\dfrac{Error}{Actual value}|\times 100 \\\\Percent \: Error = | \dfrac{\text{(Actual Value - Estimated Value)}}{Actual value}|\times 100 \\

(here |x| is such that it makes x non negative, thus, |-5| = 5, and |5| = 5)

For the given case, it is specified that:

Actual weight of dog = 32.7 pounds

Guessed weight of dog, by Charlie : 34.5 pounds.

Error = 32.7 - 34.5 = -1.8 pounds

Thus, percent error in Charlie's guess is calculated as:

\text{Percent Error} = |\dfrac{-1.8}{32.7}| \times 100 \approx 5.5\%

Hence, the percent error in Charlie’s guess is obtained approximately is given by: Option D: 5.5%

Learn more about percent error here:

brainly.com/question/25749180

3 0
2 years ago
Evaluate the integral Find the volume of material remaining in a hemisphere of radius 2 after a cylindrical hole ofradius 1 is d
algol13

You want to find the volume inside the hemisphere x^2+y^2+z^2=4 (i.e. inside the sphere but above the plane z=0) and outside the cylinder x^2+y^2=1. Call this region R.

In cylindrical coordinates, we have

\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_1^2\int_0^{\sqrt{4-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta

\displaystyle=2\pi\int_1^2 r\sqrt{4-r^2}\,\mathrm dr

\displaystyle=-\pi\int_3^0\sqrt u\,\mathrm du

(where u=4-r^2)

\displaystyle=\pi\int_0^3\sqrt u\,\mathrm du

=\dfrac{2\pi}3u^{3/2}\bigg|_0^3=2\sqrt3\,\pi

7 0
3 years ago
a crayon company recently changed its labels. it currently has 657,388 crayons with the old label and 82,923 crayons with the ne
elena-14-01-66 [18.8K]
It needs to be b or lest than that
3 0
4 years ago
Read 2 more answers
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