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2 years ago

Best answer gets brainliest

Mathematics

1 answer:

EleoNora [17]2 years ago

4 0

Answer:

A. I believe I hope its correct I'm sorry if its wrong:( I tried.

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Thu wants to play “Guess My Number,"she states. “When I triple my number and add five ,I get twenty-six.what is my number?" What

AleksandrR [38]

The <em>correct answer</em> is:

Her number is 7.

Explanation:

Let x represent her number.

She triples her number; this is represented by 3x.

She then adds 5 to this; this gives us 3x+5.

She gets 26 aas her answer. This gives us the equation:

3x+5 = 26

To solve this, first subtract 5 from each side:

3x+5-5 = 26-5

3x = 21

Divide each side by 3:

3x/3 = 21/3

x = 7

5 0

3 years ago

Read 2 more answers

Select ALL the correct answers.

Colt1911 [192]

What are the choices for this question?

6 0

3 years ago

Charlie guesses that his dog weighs 34. 5 pounds. The dog actually weighs 32. 7 pounds. What is the percent error in Charlie’s g

expeople1 [14]

Percent error is the amount of error to actual value, in percent. The percent error in Charlie’s guess is approximately: Option D: 5.5%

<h3>How to calculate the percent error?</h3>

Suppose the actual value and the estimated values after the measurement are obtained. Then we have:

Error = Actual value - Estimated value

To calculate percent error, we will measure how much percent of actual value, the error is, in the estimated value.

$\rm Percent \: Error = |\dfrac{Error}{Actual value}|\times 100 \\\\Percent \: Error = | \dfrac{\text{(Actual Value - Estimated Value)}}{Actual value}|\times 100 \\$

(here |x| is such that it makes x non negative, thus, |-5| = 5, and |5| = 5)

For the given case, it is specified that:

Actual weight of dog = 32.7 pounds

Guessed weight of dog, by Charlie : 34.5 pounds.

Error = 32.7 - 34.5 = -1.8 pounds

Thus, percent error in Charlie's guess is calculated as:

$\text{Percent Error} = |\dfrac{-1.8}{32.7}| \times 100 \approx 5.5\%$

Hence, the percent error in Charlie’s guess is obtained approximately is given by: Option D: 5.5%

Learn more about percent error here:

brainly.com/question/25749180

3 0

2 years ago

Evaluate the integral Find the volume of material remaining in a hemisphere of radius 2 after a cylindrical hole ofradius 1 is d

algol13

You want to find the volume inside the hemisphere $x^2+y^2+z^2=4$ (i.e. inside the sphere but above the plane $z=0$ ) and outside the cylinder $x^2+y^2=1$ . Call this region $R$ .