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Margarita [4]
2 years ago
12

Hello, can you please answer this question, ty

Mathematics
2 answers:
Tems11 [23]2 years ago
6 0

Answer:

y=-3

Step-by-step explanation:

the line touches the y-axis in P(0;-3)

:3

lukranit [14]2 years ago
5 0
Not completely sure but i think y is 3

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HELP PLEASE HELP ME
Marina CMI [18]

Answer:

1. k≤ 26.11 hours

2. 5 ≤ x ≤ 6

Step-by-step explanation:

1.

38.76 + 2.69k ≤ 109

2.69k ≤ 70.24

k ≤ 26.11 hours

2.

19 ≤ 4 + 3x ≤ 22

15 ≤ 3x ≤ 18

5 ≤ x ≤ 6

If my answer is incorrect, pls correct me!

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-Chetan K

5 0
3 years ago
NEED HELP IMMEDIATELY WILL GIVE BRAINLEST NO LINKS
Vikentia [17]

Answer:

fdfdsf

Step-by-step explanation:

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7 0
3 years ago
Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ
Georgia [21]

The y-intercept of a function is the point where the graph crosses the \mathbf{y = x^3 + 2x^2 - 193x - 270 }

  • The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
  • The y-intercept is -13.5
  • The standard equation of the function is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

\mathbf{x = 10}

\mathbf{x = -3}

\mathbf{x = -9}

Equate the above points to 0

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Multiply the above equations

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }

Expand

\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }

\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }

Expand

\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }

Collect like terms

\mathbf{x^3 + 12x^2 - 10x^2+ 27x  - 220x - 270 = 0 }

\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }

Replace 0 with y

\mathbf{y = x^3 + 2x^2 - 193x - 270 }

Hence, the standard form is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

Read more about graphs and functions at:

brainly.com/question/18806107

3 0
3 years ago
The average flower has 34 petals. What is the best estimate of the total number of petals on 57 sunflowers? *Math. What a mathem
saul85 [17]

34 x 57 = 1,938 petals is the correct answer :)

7 0
3 years ago
Read 2 more answers
Is 4 kilograms is egual to 4000mgs
Zigmanuir [339]
No.
So, there are 1000 milligrams in one gram, making the 4000 mgs equal to 4 grams.
There are 1000 grams in one kilogram, so 4 kilograms is equal to 4000 grams.

4000 =/= 4
So, 4 kilograms and 4000 milligrams are not equal.
7 0
3 years ago
Read 2 more answers
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