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olasank [31]
2 years ago
7

Plz help me I need help I swear I need help plz anyone help me plz help me plz I need the help from someone plz help me plz

Mathematics
1 answer:
Colt1911 [192]2 years ago
8 0

2 is the y -4 is the x I believe that this is the answer

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(a) The area of a rectangular parking lot is 7050 m².
Nastasia [14]

Answer:

75 m, 96 m

Step-by-step explanation:

a. Area = length x width

7050 = 94 x width

7050/94 = w

75 m is width

b. perimeter = 2L + 2W

356 = 2L + 2(82)

356 = 2L + 164

192 = 2L

96 m = L

6 0
2 years ago
A couple wants to install a square mirror that has an area 500 in.². To the nearest 10th of an inch what length of wood trim is
Alenkinab [10]
S·S=500. S²=500. S=√500. S=22.36. 22.4 inches for 1 side, 22.4(4)=89.6, 89.6 for all 4 :)
7 0
3 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
Solve 2(1 – x) &gt; 2x<br> this is my question for algebra
Rudik [331]

To solve this, you need to isolate/get the variable "x" by itself in the inequality:

2(1 - x) > 2x     Divide 2 on both sides

\frac{2(1-x)}{2} >\frac{2x}{2}

1 - x > x     Add x on both sides to get "x" on one side of the inequality

1 - x + x > x + x

1 > 2x        Divide 2 on both sides to get "x" by itself

\frac{1}{2} >x  or  x     (x is any number less than 1/2)

[Another way you could've solved it]

2(1 - x) > 2x     Distribute 2 into (1 - x)

(2)1 + (2)(-x) > 2x

2 - 2x > 2x      Add 2x on both sides

2 - 2x + 2x > 2x + 2x

2 > 4x    Divide 4 on both sides to get "x" by itself

\frac{2}{4} >\frac{4x}{4}

\frac{1}{2} >x

6 0
3 years ago
A single-engine plane is flying at 30 mph in the direction N 60° E. A wind is blowing from west to east at 15 mph
Ksivusya [100]

Answer:

C on Edge 2020

Step-by-step explanation:

The graph where the 60 degree angle is touching the y axis and air is above ground

7 0
3 years ago
Read 2 more answers
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