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Lorico [155]
2 years ago
11

Determine whether the table represents a linear or nonlinear function.

Mathematics
1 answer:
Alexxandr [17]2 years ago
4 0
No. Rate of change not constant. Y values increase by dif amounts
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Given P(A) = 0.51, P(B) = 0.79, and P(A or B) = 0.66, are events A and B mutually exclusive?​
pentagon [3]

Answer: No, the events are not mutually exclusive

Work Shown:

P(A and B) = P(A) + P(B) - P(A or B)

P(A and B) = 0.51 + 0.79 - 0.66

P(A and B) = 0.64

Since the result is not zero, this means the events are not mutually exclusive.

Mutually exclusive events are ones that cannot happen at the same time. Example: getting a "2" and a "3" on the same roll of a number cube.

4 0
2 years ago
All you need is in the photo please ​
lara [203]

Answer:

i don't know how to answer

Step-by-step explanation:

4 0
3 years ago
ASAP PLEASE (this is like five questions in one) GIVING 15 POINTS!!!
valentinak56 [21]

Answer:

D

21√2/2

C

C

C

Step-by-step explanation:

For all problems, the ratios of the lengths of the sides are:

30-60-90 triangle 1 : √3 : 2

45-45-90 triangle 1 : √2 : √2

Problem 3:

30-60-90 triangle at left

Hypotenuse = 11

Short leg = 11/2

Long leg = 11/2 × √3

45-45-90 triangle at right

x = 11/2 × √3 × √2 = 11√6/2

Answer: D

Problem 4:

30-60-90 triangle at top

Hypotenuse = 7√3

Short leg = 7√3/2

Long leg = 7√3/2 × √3 = 7 × 3/2 = 21/2

45-45-90 triangle at right

x = 21/2 × √2 = 21√2/2

Answer: 21√2/2

Problem 7:

30-60-90 triangle

Long leg = 4√3

Short leg = y = 4√2/2 = 2√2

Answer: C.

Problem 6:

30-60-90 triangle at left

Hypotenuse = 12√6

Short leg = 12√6/2 = 6√6

Long leg = 6√6 × √3 = 6√2√3√3 = 18√2

45-45-90 triangle at right

x = 18√2/√2 = 18

Answer: C.

Problem 8:

45-45-90 triangle

Hypotenuse = 2

Leg = y = 2/√2 = 2√2/(√2√2) = √2

Answer: C.

5 0
2 years ago
What is the place value of 5 in 3,152,308
dimulka [17.4K]

Ten-thousands place value

6 0
4 years ago
Plsss help I don't know how to graph I will give brainiest!
Anastasy [175]

Answer: (2, 5)

Step-by-step explanation:

y = 2x + 1 y = 4x − 3

Eliminate the equal sides of each equation and combine.

2x + 1 = 4x − 3

Solve 2x + 1 = 4x − 3 for x.

Move all terms containing x to the left side of the equation.

Subtract 4x from both sides of the equation.

2x + 1 − 4x = −3

Subtract 4x from 2x.

−2x + 1 = −3

Move all terms not containing x to the right side of the equation.

Subtract 1 from both sides of the equation.

−2x = −3 − 1

Subtract 1 from −3.

−2x = −4

Divide each term by −2 and simplify.

x = 2

Evaluate y when x = 2.

Substitute 2 for x. y = 4 (2) − 3

Simplify 4 (2) − 3.

Multiply 4 by 2.

y = 8 − 3

Subtract 3 from 8.

y = 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

(2, 5)

The result can be shown in multiple forms.

Point Form:

(2, 5)

Equation Form:

x = 2, y = 5

4 0
3 years ago
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