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1 year ago

Given P(A) = 0.51, P(B) = 0.79, and P(A or B) = 0.66, are events A and B mutually exclusive?

Mathematics

1 answer:

pentagon [3]1 year ago

4 0

Answer: No, the events are not mutually exclusive

Work Shown:

P(A and B) = P(A) + P(B) - P(A or B)

P(A and B) = 0.51 + 0.79 - 0.66

P(A and B) = 0.64

Since the result is not zero, this means the events are not mutually exclusive.

Mutually exclusive events are ones that cannot happen at the same time. Example: getting a "2" and a "3" on the same roll of a number cube.

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Given P(A) = 0.51, P(B) = 0.79, and P(A or B) = 0.66, are events A and B mutually exclusive?​

Given P(A) = 0.51, P(B) = 0.79, and P(A or B) = 0.66, are events A and B mutually exclusive?