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2 years ago

Plsss help I don't know how to graph I will give brainiest!

Mathematics

1 answer:

Anastasy [175]2 years ago

4 0

Answer: (2, 5)

Step-by-step explanation:

y = 2x + 1 y = 4x − 3

Eliminate the equal sides of each equation and combine.

2x + 1 = 4x − 3

Solve 2x + 1 = 4x − 3 for x.

Move all terms containing x to the left side of the equation.

Subtract 4x from both sides of the equation.

2x + 1 − 4x = −3

Subtract 4x from 2x.

−2x + 1 = −3

Move all terms not containing x to the right side of the equation.

Subtract 1 from both sides of the equation.

−2x = −3 − 1

Subtract 1 from −3.

−2x = −4

Divide each term by −2 and simplify.

x = 2

Evaluate y when x = 2.

Substitute 2 for x. y = 4 (2) − 3

Simplify 4 (2) − 3.

Multiply 4 by 2.

y = 8 − 3

Subtract 3 from 8.

y = 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

(2, 5)

The result can be shown in multiple forms.

Point Form:

(2, 5)

Equation Form:

x = 2, y = 5

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Find the value of n 1) 15/40 =n/3

stepladder [879]

Answer:

n = 1.125

Step-by-step explanation:

$\frac{15}{40} = \frac{n}{3}$

(Use Cross Product)

40n = 15 × 3

40n = 45

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3 years ago

Solve:

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Answer:

1. Infinitely Many Solutions

2. Zero Solutions

3. One Solution ( x = 6 )

Step-by-step explanation:

12x + 8 = 2( 6x + 4 )

12x + 8 = 12x + 8

2( 2x + 1 ) = 4x + 3

4x + 2 = 4x + 3

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Hopefully this helps!

Brainliest please?

8 0

2 years ago

The ice cream shop has 80 different possible sundaes consisting of 1 flavor of ice cream, 1 syrup, and 1 candy topping. If the i

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4: 80*5*4 
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3 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

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3 years ago

Who is correct chris or sam

Advocard [28]

Lacey, because you have to do the opposite when you want to get rid of a number. She subtracted 20 because it was originally positive 20. Chris messed up and did not do the opposite, subtraction, and instead he added 20

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3 years ago

Read 2 more answers