You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
<span>6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player. </span>
<span>So the bleachers are 9/2 x 6 ft = 27 ft. </span>
<span>For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216. </span>
<span>So the stage will have dimensions 216 times larger than 1.75" by 3". </span>
<span>That would be 31ft 6ins x 54ft. </span>
Answer:
y=3/16x + 1/8
Step-by-step explanation:
2+16y=3x+4
16y=3x+4-2
16y=3x+2
y= 3/16x + 1/8
The answer would be C., because when you actually divide <span>15.39 ÷ 0.95, it's 16.2, and so when you round that it would turn to 16. c:</span>
161%
Step-by-step explanation:
They are asking percentage so we know we going to ×100%
4943 AS A PERCENTAGE OF 3076

161%
Answer:
Line segments are congruent if they have the same length. However, they need not be parallel. They can be at any angle or orientation on the plane. In the figure above, there are two congruent line segments. If you drag any of the four endpoints, the other segment will change length to remain congruent with the one you are changing.