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Alekssandra [29.7K]

2 years ago

13

Mrs. Douglas packs candy bars into boxes for the members of the school band to sell as a fundraiser. Each candy bar weighs 5.75

ounces, and the empty box weighs 2.95 ounces. If the algebraic rule y = 5.75x + 2.95 represents the total weight of the packed box, what does the variable x represent?
a. Weight of each candy bar inside a box
b. Total weight of a box filled with candy bars
c. Total number of boxes filled with candy bars
d. Number of candy bars packed into a box

2 answers:

olchik [2.2K]2 years ago

8 0

Answer:

d

Step-by-step explanation:

Mars2501 [29]2 years ago

7 0

Answer: D
Explanation: “each candy bar weighs 5.75 ounces” meaning 5.75x would represent 5.75• the number of candy bars

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Someone please help for brainiest and thanks.. No fake answers or you get reported

bagirrra123 [75]

Hello from MrBillDoesMath!

Answer:

12/5

Discussion:

Note that 10 is a common denominator of both denominators:

9/5 = (9*2)/(5*2) = 18/10

- ( -6/10) = + (6/10)

So the original problem is equivalent to

18/10 + 6/10 =

(18 +6)/10 =

24/10 =

(2*12)/ (2*5) => cancelling the common factor "2"

12/5 =

2 and 2 fifths =

22/5 (though this looks like (22)/5!)

Thank you,

MrB

6 0

3 years ago

Marcia has $84 less than three times as much as sue. together they have $132. how much money does marcia have?

Brut [27]

Let x = sue
and then let 3x-84 = marcia
therefore
(x)+(3x-84)=132
4x-84=132
4x=216
x=54

however just solving for x doesnt completely solve. it only shows sues money because x = sue
for marcia
3x-84
3(54)-84
162-84
78

therefore Marcia has 78$.

5 0

3 years ago

What is the ratio 175 to 250 written in fraction in LOWEST TERMS?

Lana71 [14]

For 175 : 250 divide them both by 25 to get $\frac{7}{10}$ < $\frac{175}{250}$
25 goes into 175 > 7 times > 25 into 250 is 10 times! > $\frac{7}{10}$
For the second one 16 : 40 just divide the top and bottom by 8 since 8 is a common factor of both which will give us $\frac{2}{5}$ .
8 goes into 16, 2 times and 40, 5 times.

5 0

3 years ago

Read 2 more answers

Prove the divisibility:<br><br>45^45·15^15 by 75^30

garri49 [273]

Answer:

$3^{75}$ .

Step-by-step explanation:

We have been an division problem: $\frac{45^{45}*15^{15}}{75^{30}}$ .

We will simplify our division problem using rules of exponents.

Using product rule of exponents $(a*b)^n=a^n*b^n$ we can write:

$45^{45}=(9*5)^{45}=9^{45}*5^{45}$

$15^{15}=(3*5)^{15}=3^{15}*5^{15}$

$75^{30}=(15*5)^{30}=15^{30}*5^{30}$

Substituting these values in our division problem we will get,

$\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}$

$\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}$

Using product rule of exponents $(a*b)^n=a^n*b^n$ we will get,

$\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}$

$\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}$

Using power rule of exponents $a^n*a^m=a^{n+m}$ we will get,

$\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}$

$\frac{3^{105}*5^{60}}{3^{30}*5^{60}}$

$\frac{3^{105}}{3^{30}}$

Using quotient rule of exponent $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{3^{105}}{3^{30}}=3^{105-30}$

$3^{105-30}=3^{75}$

Therefore, our resulting quotient will be $3^{75}$ .

7 0

3 years ago

Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.

gogolik [260]

Answer:

a = 4

b = 4

Step-by-step explanation:

This is a special right triangle with angle measures of 45° 45° 90° and side lengths x x x√2

3 0

3 years ago