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Zielflug [23.3K]
2 years ago
9

find the length of DE if D is between points C and E, CD = 6.5 centimeters, and CE = 13.8 centimeters.

Mathematics
1 answer:
grin007 [14]2 years ago
5 0

Answer:

DE = 7.3 cm

Step-by-step explanation:

All you have to do is take the length of the full line (13.8 cm) and subtract it by the first part (6.5 cm). Doing this gets you the final length of DE with is 7.3 cm.

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Find the missing side lengths. Leave your answers as radicals in simplest form. Please help!! Due today
Nataly_w [17]

Answer:

m = 10\sqrt 3

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Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

\sin(60) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60) = \frac{m}{20}

Make m ths subject

m = 20 * \sin(60)

\sin(60) =\frac{\sqrt 3}{2}

So, we have:

m = 20 *\frac{\sqrt 3}{2}

m = 10\sqrt 3

Considering the given angle again, we have:

\cos(60) = \frac{Adjacent}{Hypotenuse}

This gives:

\cos(60) = \frac{n}{20}

Make n the subject

n = 20 * \cos(60)

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So, we have:

n = 20 *\frac{1}{2}

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5 0
2 years ago
Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

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0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

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0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0
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algol13

Answer:

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Step-by-step explanation:

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