Answer:
50 micro mol/min
Explanation:
So, we have the following parameters which are going to help us in solving this particular Question or problem;
=> For the wild type enzyme, the value for the Maximum velocity = 100 micromol/min.
=> For the mutant type enzyme, the value for the Maximum velocity = 1 micromol/min.
So, we can determine or calculate the value for the initial velocity for each of the enzyme type by using the formula below;
Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.
Therefore, for the wild type enzyme; the Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.
Initial velocity =( 10mM × 100micromol/min) ÷ ( 10mM + 10 mM ) = 50 micro mol/min.
Initial velocity for the wild type enzyme = 50 micro mol/min.
(flowering plants, conifers, ferns and their allies) and of Bryophytes. plant species.
mammals, reptiles, grassland animals, freshwater animal, marine animals. animal species
Answer:
Explanation:
Bacteria capsule contain poly-γ-d-glutamic acid and also possesses antiphagocytic properties .
Gram positive cell wall peptidoglycan.
Fimbriae contain adhesin which make them to attach to a base and counter shear force and obtain food.
Pili contain oligomeric proteins which is hair like structure.
Endospores consists of DNA, ribosomes and dipicolinic acid.
RIBOSOMES consist of ribosomal RNA and proteins.
Plasmid consist of circular DNA.
Plasma membranes consist lipid bilayer.
Chemotherapy and/or stem cell transplant
The F1 offspring of Mendel's classic pea plant crosses always looked like one of the two parental varieties because he crossed a homozygous dominant plant with a homozygous recessive plant so each plant received one recessive allele and one dominant allele. All of the plants looked like one plant because the dominant allele overshadowed the recessive allele
