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tia_tia [17]
3 years ago
7

A. 2x4 + 21x2 +3x -2B. 2x4 + 9x2 -2C. 3x2 + 6x+ 1 D. 2x4 + 9x3 +12x2 + 3x -2 ​

Mathematics
1 answer:
Inga [223]3 years ago
6 0
You need to foil, The answer is D
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Evaluate: if x = 3 and y = 6 x(2x + x2 – 8y + 16)​
kumpel [21]

Answer:

-60

Step-by-step explanation:

Og problem: x(2x + 2x - 8y + 16)

Substitution: 3(6 + 6 - 48 + 16)

Solve: 3(12 - 48 + 16)

3(-36 + 16)

3(-20) = -60

3 0
3 years ago
What is the area of a circle with a diameter of 15. 8cm? To the nearest hundredth
klio [65]

Answer:

see below

Step-by-step explanation:

First we need to find the radius

r =d/2 = 15.8/2 = 7.9 cm

The area of a circle is given by

A = pi r^2

   = pi ( 7.9) ^2

   =62.41 pi

Using 3.14 for pi

195.9674  

To the nearest hundredth

195.97

Using the pi button

196.0667975

To the nearest hundredth

196.07

7 0
2 years ago
Midway through the fundraiser, Mrs Little, the sponsor, discovers a container of buttermilk in the back of the fridge. It has 6
solong [7]

Answer: 6 recipes

Step-by-step explanation: Just divide the 6 cups of buttermilk by 7/8 because each recipe need 7/8 cup of butter milk. You will get a number like this 6.857142857142857 (there are probably more decimals that come after it.) But, all the numbers after the 6 are useless because more recipes can't be made with those because you need at least 7/8  cups for one recipe. So, this will make 6 recipes. Hope this helps!

7 0
3 years ago
James is reading a book that is 1400 pages he will read the same number of pages each day if he reads the book in 7 days how man
Novay_Z [31]
He will read 200 pages a day.
7 0
3 years ago
Read 2 more answers
Given: PRST is a square
xxTIMURxx [149]

Answer:

(1-\sqrt{2})a^2

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a

Thus,

MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a

Consider isosceles triangle MSC. In this triangle

MS=MC=(\sqrt{2}-1)a.

The area of this triangle is

A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}

Consider right triangle PTS. The area of this triangle is

A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2

5 0
3 years ago
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