Answer:
The range here is 85
Step-by-step explanation:
Here, we want to calculate the range of the data
Mathematically, the range is defined as the difference between the lowest value and the highest value in the dataset
From the given data points, the highest value is 189, while the lowest value is 104
So the range is the difference between the two which is;
189-104 = 85
Answer:
Kindly check explanation
Step-by-step explanation:
H0 : μ = 5500
H1 : μ > 5500
The test statistic assume normal distribution :
Test statistic :
(Xbar - μ) ÷ s/sqrt(n)
(5625.1 - 5500) ÷ 226.1/sqrt(15) = 2.1429 = 2.143
Pvalue from test statistic :
The Pvalue obtained using the calculator at df = 15 - 1 = 14 is 0.025083
α = 0.05
Since ;
Pvalue < α
0.025083 < 0.05 ; Reject H0
The confidence interval :
Xbar ± Tcritical * s/sqrt(n)
Tcritical at 95% = 1.761 ;
margin of error = 1.761 * 226.1/sqrt(15) = 102.805
Lower boundary : (5625.1 - 102.805) = 5522.295
(5522.295 ; ∞)
The hypothesized mean does not occur within the constructed confidence boundary. HENCE, there is significant eveidbce to support the claim that the true mean life of a biomedical device is greater than 5500
Answer:
-3, -1, 1
Step-by-step explanation:
the x-coordinates are the domain
Answer:
no 3
Step-by-step explanation:
using sine rule of trigonometry
a/sine A=b/sine B=c/sin C
two sides were given and one angle is also given
sides are represented by small alphabet
and angles are represented by capital letters
a=8.7
b=15
c=is not given
B=90
8.7/sine A=15/sine 90=c/sine C
then we use the complete one which is B to solve for the remaining
- solving for A
8.7/sine A=15/ sine90
cross multiply
15sine A=8.7*sine 90
15sineA=8.7*1
divide the by 15
sineA=8.7/15
sineA=0.58
A=sine -1 0.58
A=35.45
A=36
I supposed you mean similar and not congruent.
If kjn ≡ lmn, the kj would be equal to lm which in your question, is not
Assumed kjn is similar to lmn
scale = 17.5 ÷ 10 = 1.75
Therefore,
kj = 17.5 cm (given)
jn = 8 x 1.75 = 14 cm
kn = 6 x 1.75 = 10.5 cm
Perimeter = 17.5 + 14 + 10.5 = 42 cm
Answer: 42 cm
