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snow_tiger [21]
3 years ago
9

What role does ethics play in choosing and applying a depreciation method?what role does ethics play in choosing and applying a

depreciation method? ​
Business
1 answer:
Minchanka [31]3 years ago
8 0

Answer:

Explanation:

Ethics demands reasons to be given for changing from one depreciation method to another. There are three depreciation methods that are applicable including double-declining balance technique, unit of production technique, and straight-line technique.  

Changing from one depreciation method to another must be done in the best interests of shareholders and reasons for such a change must be disclosed. Therefore, ethics requires a company to reveal the changes in depreciation method and adhere to the accounting principles related to the method used.  

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Which of the following is not included in the heading of a cover letter
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Since no choices are presented, I'll just list down the parts of a cover letter.

A cover letter is a one page document that is attached to a resume. It has 5 parts.

1) The Salutation : Dear Hiring Manager,
2) The Grab - Opening Paragraph - introduction about yourself and your immediate qualification on the position you are applying
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What would happen to the buying power of your investment after one year if your rate of return was 8% and the rate of inflation
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Dude why did you put this question like 5 times??
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4 years ago
. Assume a home buyer puts 20% down on a $250,000 house and uses a mortgage to borrow the rest. What will the amount of the mort
Elina [12.6K]
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7 0
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Automobile repair costs continue to rise with the average cost now at $367 per repair.† Assume that the cost for an automobile r
vovikov84 [41]

Answer:

a)  0.1728

b)  0.09183

c) 0.7354

d) $ 222.25

Explanation:

Given

mean = \mu = $367

Standard deviation = \sigma =$88

Cost of automobile repair is normally distributed.

a) We have to find P( x > 450 )

P( x > 450 ) = 1 - P( x <= 450 )

Using excel function,   P( x <= x ) = NORMDIST (x,  \mu, \sigma, 1 )

P( x > 450 )   = 1 - NORMDIST( 450 , 367, 88, 1 )

= 1 - 0.8272 = 0.1728

P( x > 450 ) = 0.1728

b)  P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( x < 250 ) = 0.09183

c) P( 250 < x < 450 ) = P( x <450 ) - P( x < 250 )

P( x <450 ) = NORMDIST( 450 , 367, 88, 1 ) = 0.8272

P( x < 250 ) = NORMDIST( 250 , 367, 88, 1 ) = 0.09183

P( 250 < x < 450 ) = 0.8272 - 0.09183 = 0.7354

P( 250 < x < 450 ) = 0.7354

d) We have P( X < a ) = 0.05

We have to find a.

Using Excel, = NORMINV ( Probability, \mu, \sigma )

a = NORMINV ( 0.05 , 367, 88 ) = 222.2529

Cost = $ 222.25

8 0
3 years ago
Probett's Auto Body Repair Shop had revenues that averaged $90,000 per week in April and $80,000 per week in May. During both mo
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Answer:

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good luck ❤

6 0
3 years ago
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