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SIZIF [17.4K]
3 years ago
8

Suppose seven pairs of similar-looking boots are thrown together in a pile. What is the minimum number of individual boots that

you must pick to be sure of getting a matched pair? Why?Since there are 7 pairs of boots in the pile, if at most one boot is chosen from each pair, the maximum number of boots chosen would be . It follows that if a minimum of Incorrect: Your answer is incorrect. boots are chosen, at least two must be from the same pair.
Mathematics
1 answer:
VikaD [51]3 years ago
8 0

Answer:

We must pick at least 8 individual boots to be sure of picking at least one matching pair as explained from the pigeon hole principle.

Step-by-step explanation:

From pigeonhole principle, if k is a positive integer and k + 1 or more objects are placed into k boxes, then there is at least one box containing 2 or more objects.

Now, since we have 7 pairs of similar looking boots, thus, number of single boots we have will be;

Number of single boots = 7 x 2 = 14

Now, if we select 7 boots from the 14,then there's a possibility of selecting exactly 1 from each pair. Thus, we will not get a matching pair.

Whereas if we select 8 boots from the 14 single boots, then by the pigeon hole principle, at least 2 of the boots will need to be from the same pair. Hence we can pick at least 8 individual boots to be sure of picking at least one matching pair.

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Dante plans to put 80% of his paycheck into a savings account and spend the other 20%. His paycheck this week was 295$. About ho
IgorLugansk [536]

80% × $295 = 80/100 × $295 = $236

Dante will put $236 into his savings account.

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3 years ago
I’am between 750 and 850. I have 3 ones and no tens.
il63 [147K]
Maybe something like 811.1?
7 0
4 years ago
An oval track is made by erecting semicircles on each end of a 60m by 120m rectangle. Find the length of the track and the area
vodomira [7]
Refer to the figure shown below.

Because the question states that the semi circles are at the ends of the rectangle, each semicircle has a radius of 30 m.

The circumference of the oval is
2π(30) + 2*120 = 60π + 240 m = 428.5 m

The area of the oval is 
π(30²) + 60*120 = 900π + 7200 m² = 1.0027 x 10⁴ m²

Note:
If the semi circles are placed on the 120-m sides of the rectangle, then similar calculations yield:
Circumference = 120π + 120 m = 497 m
Area = 3600π + 7200 m² = 1.851 x 10⁴ m²

Answer:
If the semi circles are placed on the 60-m sides of the rectangle, then
Circumference = 60π + 240 m, or 428.5 m
Area = 900π + 7200 m², or 1.0027 x 10⁴ m²

if the semi circles are placed on the 120-m sides of the rectangle, then
Circumference = 120π + 120 m, or 497 m
Area = 3600π + 7500 m², or 1.851 x 10⁴ m²


3 0
4 years ago
Help !!!!!!!!!!!!!!!! plz
vovikov84 [41]

Answer:

5 > n + 10

8 x 7 < n

n/3 + 1

6 x 8 - 10 < n

n - 1 x n

n x -n + 7

4 0
3 years ago
William is drafting his fantasy basketball team. He needs to select one player for each position. The following table shows how
PilotLPTM [1.2K]

Answer: 15120

Step-by-step explanation:

Given: The number of players at point guard = 10

The number of players at shooting guard = 12

The number of players at small forward = 7

The number of players at power forward = 2

The number of players at center = 9

Then, the number of different teams William could draft is given by :-

10∗12∗7∗2∗9=15120

Hence, William could draft 15120 different teams.

7 0
2 years ago
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