Well formatted version of the question can be found in the picture attached below :
Answer:
Both Carlos and Irene
Step-by-step explanation:
Given the expression (28x - 8)
Carlos : 2(14x - 4)
Danny : 7(4x - 1)
Irene : 4(7x - 2)
The factored expression Given by Carlos, Irene and Danny can be expanded to check if it gives the same expression as that Given in the question :
Carlos :
2(14x - 4)
2*14x - 2*4
28x - 8
Danny :
7(4x - 1)
7*4x - 7*1
28x - 7
Irene :
4(7x - 2)
4*7x - 4*2
28x - 8
From.the expanded solutions obtained ;
Both Carlos and Irene's solution corresponds to the factored form of the original equation and are Hence correct
Ok so how I get taught to do this is you need to know the basics of algebra if you know that then respond and I’ll tell you how to solve that
Answer:
Tn = 64-4n
Step-by-step explanation:
The nth term of an AP is expressed as:
Tn = a+(n-1)d
a is the common difference
n is the number of terms
d is the common difference
Given the 6th term a6 = 40
T6 = a+(6-1)d
T6 = a+5d
40 = a+5d ... (1)
Given the 20th term a20 = -16
T20 = a+(20-1)d
T20 = a+19d
-16 = a+19d... (2)
Solving both equation simultaneously
40 = a+5d
-16 = a+19d
Subtracting both equation
40-(-16) = 5d-19d
56 = -14d
d = 56/-14
d = -4
Substituting d = -4 into equation
a+5d = 40
a+5(-4) = 40
a-20 = 40
a = 20+40
a = 60
Given a = 60, d = -4, to get the nth term of the sequence:
Tn = a+(n-1)d
Tn = 60+(n-1)(-4)
Tn = 60+(-4n+4)
Tn = 60-4n+4
Tn = 64-4n
