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Mumz [18]
3 years ago
10

Find the area of the shaded region

Mathematics
1 answer:
vodomira [7]3 years ago
6 0
C is the area that is shaded region
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How many times does 42 go into 239?
Ainat [17]
239/42=5...29
42 goes into 239 5 times
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3 years ago
Associations In Data:Question 10
Karo-lina-s [1.5K]

Answer:

\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9

|62-78.9| = 16.9

|63-78.9| = 15.9

|68-78.9| = 10.9

|72-78.9| = 6.9

|79-78.9| = 0.1

|80-78.9| = 1.1

|83-78.9| = 4.1

|93-78.9| = 14.1

|94-78.9| = 15.1

|95-78.9| = 16.1

MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}

And replacing we got:

MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12

And the best anwer is

10.12

Step-by-step explanation:

We have the following data given:

62 63 68 72 79 80 83 93 94 95

And we need to begin finding the mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9

Now we can find the mean absolute deviation like this:

|62-78.9| = 16.9

|63-78.9| = 15.9

|68-78.9| = 10.9

|72-78.9| = 6.9

|79-78.9| = 0.1

|80-78.9| = 1.1

|83-78.9| = 4.1

|93-78.9| = 14.1

|94-78.9| = 15.1

|95-78.9| = 16.1

And finally we can find the mean abslute deviation with the following formula:

MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}

And replacing we got:

MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12

And the best anwer is

10.12

8 0
3 years ago
NEED HELP please and thank you hehe
Lesechka [4]

Answer:

113

Step-by-step explanation:

it's the x outside right?

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What is the slope of the line shown on the graph to the​ right?
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Is 1 up and 2 to the side
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What is standard form for 6.43999001 x 10^8
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6.43999001  
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you answer is (643, 999, 001)
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