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2 years ago

7

sam and jennna decide to purchase a tv on black friday. the sale price is $499. if jenna pays $123 more than sam, how much did s

am pay?

1 answer:

stellarik [79]2 years ago

6 0

Answer:

Sam would pay $188 and jenna would pay $311.

Step-by-step explanation:

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2w(w2 + 3w - 5) + 3w3 + 2(w2 + 1)

marysya [2.9K]

Answer:

=5w3+8w2−10w+2

Step-by-step explanation:

Simplify

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Combine like terms

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Combine like terms

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sorry if it don't make sense ;c

7 0

3 years ago

-7x is less than or equal to -21

julsineya [31]

The answer is x=3
if you divide each by -7 to isolate x, it’s equal to positive three because 2 negatives make a positive

6 0

2 years ago

The points plotted below are on the graph of a polynomial. In what range of

Irina-Kira [14]

Answer:

the answer is 0 to 1 and 3 to 4

7 0

2 years ago

if 2 people answered your question and they were both right but only one of them explained they answer who should I give brainli

lakkis [162]

The person who explained the answer because you can see how they got the answer or the evidence they used to get the answer

5 0

3 years ago

How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title

kotegsom [21]

Let $t=\sqrt y$ , so that $t^2=y$ , $t^4=y^2$ , and $\mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}$ . Then

$\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}$

Now let $y=\sqrt2\tan z$ , so that $\mathrm dy=\sqrt2\sec^2z\,\mathrm dz$ . Then

$\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C$

Transform back to $y$ to get

$\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C$

and again to get back a result in terms of $t$ .

$\dfrac1{2\sqrt2}\arctan\left(\dfrac{t^2}{\sqrt2}\right)+C$

3 0

3 years ago