All categories

4 years ago

a tree 5 ft tall grows an avarage of 8 in. each year. write and graph an equation to model the tree's height h after x years.

1 answer:

5 0

Y=8x+5 would be the equation since every year,x represents year, it would be time by 8 and add 5 since that the original height it started.

You might be interested in

use this information for items 1-3. Aaron has $65 to rent a bike in the city . It costs $15 per hour to rent a bike. The additio

marissa [1.9K]

Answer:

Step-by-step explanation:

What we are expected to solve for that the problem did not expressly state is most likely the number of hours that you could ride for an amount of $65.

firstly we need to model the inequality (equation) for this scenario.

the constant fee= $3 additional fee for helmet

$3+15n\leq 65\\\\$

We can now solve for n since the above inequality satisfies the condition presented in the problem statement.

$3+15n\leq 65\\\\15n\leq65-3\\\\ 15n\leq 62$

Divide both sides by 15 to find n

$n\leq 62/15\\\\n\leq 4hrs -8min$

8 0

3 years ago

If 3,000 bacteria, with a growth constant (k) of 2.8 per hour, are present at the beginning of an experiment, in how many hours

Ivenika [448]

Given:

Initial number of bacteria = 3000

With a growth constant (k) of 2.8 per hour.

To find:

The number of hours it will take to be 15,000 bacteria.

Solution:

Let P(t) be the number of bacteria after t number of hours.

The exponential growth model (continuously) is:

$P(t)=P_0e^{kt}$

Where, $P_0$ is the initial value, k is the growth constant and t is the number of years.

Putting $P(t)=15000,P_0=3000, k=2.8$ in the above formula, we get

$15000=3000e^{2.8t}$

$\dfrac{15000}{3000}=e^{2.8t}$

$5=e^{2.8t}$

Taking ln on both sides, we get

$\ln 5=\ln e^{2.8t}$

$1.609438=2.8t$ $[\because \ln e^x=x]$

$\dfrac{1.609438}{2.8}=t$

$0.574799=t$

$t\approx 0.575$

Therefore, the number of bacteria will be 15,000 after 0.575 hours.

4 0

3 years ago

Solve by Elimination<br> 2x+5y=9<br> 3x-5y=11

shepuryov [24]

Answer:

x = 4 , y = ⅕

Step-by-step explanation:

2x + 5y = 9 (1)

3x - 5y = 11 (2)

Add (1) and (2)

5x = 20

x = 4

Using (1), find y

2(4) + 5y = 9

5y = 1

y = ⅕

8 0

3 years ago

Read 2 more answers

How can I find the area of a rectangle with a rectangle the size of w- 2in and l- 5 in. I need two ways and i need a lot of easy

Anvisha [2.4K]

Here's one way: A=WxL So in this case, it's 2x5 You would draw the rectangle, label one side 2 in. and the other 5 in. Draw an arrow from each no./side and put x underneath the line so that its 2 —x— 5 (2, line, x, line, 5. With x under line)

6 0

3 years ago

20 Point!

ludmilkaskok [199]

determinant: $\sqrt{b^2-4ac}$

(a) $x^2+4x+5=0\\D=4^2-4\cdot1\cdot5={-4}\\D$

D<0 means there are no real roots. there are two complex roots with imaginary components.

(b) D=16+20=36>0

D>0 means there are two real roots

D=0 means there is one real root with multiplicity 2

7 0

4 years ago