<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
Answer:
In 22 minutes the remaining cell phone battery will be unknown.
In a of minutes the remaining cell phone battery will be 50%.
Step-by-step explanation:
Answer:
v1 = 1
Step-by-step explanation:
Solve for v1:
3 v1 - 3 = 0
Add 3 to both sides:
3 v1 + (3 - 3) = 3
3 - 3 = 0:
3 v1 = 3
Divide both sides of 3 v1 = 3 by 3:
(3 v1)/3 = 3/3
3/3 = 1:
v1 = 3/3
3/3 = 1:
Answer: v1 = 1
Answer:
Step-by-step explanation:
Hello !
(4,4*2,4) + (3,14 * 2,2² )/2 =
10,56 + 7,60 = 18,2 m²
Evaluate abs(-4 b - 8) + abs(-b^2 - 1) + 2 b^3 where b = -2:
abs(-4 b - 8) + abs(-b^2 - 1) + 2 b^3 = abs(-4 (-2) - 8) + abs(-1 - (-2)^2) + (-2)^3×2
(-2)^2 = 4:
abs(-4 (-2) - 8) + abs(-4 - 1) + 2×(-2)^3
-4 (-2) = 8:
abs(8 - 8) + abs(-4 - 1) + 2×(-2)^3
8 - 8 = 0:
abs(0) + abs(-1 - 4) + 2×(-2)^3
-1 - 4 = -5:
abs(0) + abs(-5) + 2×(-2)^3
(-2)^3 = (-1)^3×2^3 = -2^3:
abs(0) + abs(-5) + 2×-2^3
2^3 = 2×2^2:
abs(0) + abs(-5) + 2 (-2×2^2)
2^2 = 4:
abs(0) + abs(-5) + 2 (-2×4)
2×4 = 8:
abs(0) + abs(-5) + 2 (-8)
Since 0 is at the origin, then abs(0) = 0:
abs(-5) - 8×2
Since -5<=0, then abs(-5) = 5:
5 - 8×2
2 (-8) = -16:
-16 + 5
5 - 16 = -11:
Answer: -11
