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2 years ago

Mary and Kyle together sold 225 candy bars for a fund raiser. Kyle sold twice as many candy bars as Mary.

Mathematics

2 answers:

NARA [144]2 years ago

5 0

Answer:

Mary has 76.5, and Kyle has 178.5.

Aleks04 [339]2 years ago

5 0

Answer:

Kyle sold 150 candy bars and Mary sold 75.

Step-by-step explanation:

the equation you want to use is 2x + x = 225.

the 2x is for Kyle and the x is for Mary.

then you can simplify to make it 3x = 225, divide both sides by 3 which gives you an x value of 75, and then you plug it into the original equation, which gives you:

2x + x = 2(75) + 75 = 225

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What is the value of x?

viktelen [127]

Answer:

x = 113

Step-by-step explanation:

The sum of the angles of a triangle are 180 degrees

37+54+ x-24 = 180

Combine like terms

67+x = 180

Subtract 67 from each side

67-67+x = 180-67

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6 0

3 years ago

3x2 - 2x = 0 Factorise and solve

malfutka [58]

Solve : 3x-2 = 0

Add 2 to both sides of the equation :

3x = 2

Divide both sides of the equation by 3:

x = 2/3 = 0.667

Two solutions were found :

x = 2/3 = 0.667

x = 0

hope this helped

6 0

3 years ago

Read 2 more answers

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

Camera 2nd has to cover the maximum angle, i.e. $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$