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Alinara [238K]
3 years ago
14

A number that can be written as a/b where a and b are integers, but b is not equal to zero

Mathematics
1 answer:
KIM [24]3 years ago
5 0
Rational number is your answer 
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Write the first 4 terms of the sequence defined by the given rule f(n)=n2 -1
Softa [21]

Answer:

<h2>0, 3, 8, 15</h2>

Step-by-step explanation:

Substitute n = 1, n = 2, n = 3 and n = 4 to the equation f(n) = n² - 1:

f(1) = 1² - 1 = 1 - 1 = 0

f(2) = 2² - 1 = 4 - 1 = 3

f(3) = 3² - 1 = 9 - 1 = 8

f(4) = 4² - 1 = 16 - 1 = 15

5 0
3 years ago
PLEASE HELP ME !! WILL GIVE BRAINLIEST!!
PolarNik [594]
B is a times b
C is  also a times b

sorry im stuck on the rest

6 0
3 years ago
ASAP HELPP PLEASE ?
Kipish [7]
<span>1. h = -16t² + vt + c
⇒ vt = 16t² + h - c
⇒ v = 16t + (h-c)/t

2. c = 5 ft
t = 3s
h = 131 ft

v = 16*3 + (131-5)/3 = 48 + 42 = 90 ft/s

when t=0, velocity is not defined. That means at t=0, there is no velocity of the t-shirt or it is 0.
</span>
5 0
3 years ago
Read 2 more answers
Solving multi step equations
hichkok12 [17]

The no-brain way to do it is to

  1. subtract one side from both sides so you have <em>(something) = 0</em>.
  2. divide by the coefficient of the variable.
  3. add the opposite of the constant.

Of course, at some point, you need to simplify the equation so you have something like

... ax + b = 0 . . . . . . where <em>a</em> and <em>b</em> are some constants that may be positive or negative

17) Subtract the right side.

... 10(x +3) -(-9x -4) -(x -5 +3) = 0

... 10x + 30 +9x +4 -x +5 -3 = 0 . . . . . eliminate parentheses

... x(10+9-1) +(30+4+5-3) = 0 . . . . . . . collect terms

... 18x +36 = 0 . . . . . . . . . . . . . . . . . . . simplified

... x + 2 = 0 . . . . . . . . . . . . . . . . . . . . . .divide by 18, the coefficient of x

... x = -2 . . . . . . . . . . . . . . . . . . . . . . . . add the opposite of the constant

19) Add the opposite of the left side.

... 0 = -9(1 +7x) +12(x -12)

... 0 = -9 -63x +12x -144 . . . . . . eliminate parenthses

... 0 = -51x -153 . . . . . . . . . . . . . simplify

... 0 = x +3 . . . . . . . . . . . . . . . . . divide by -51, the coefficient of x

... -3 = x . . . . . . . . . . . . . . . . . . . add the opposite of the constant

_____

If you examine the variable's coefficients you can make a choice of side to subtract that results in a positive coefficient of the variable.

This method puts variable and constant together until the end. The approach usually taught is to separate the variable terms and constant terms. (The number of steps required is the same either way.)

The reason this is "no brain" is that it always works and requires no judgment as to what you add or subtract from where. Applying a little judgment as described above can make it so you're mostly working with positive numbers, but the method works whether the numbers are positive or negative.

6 0
3 years ago
Amari claims that a rectangle is sometimes a parallelogram but a parallelogram is always a
Maslowich

Answer:

The statement is false.

Step-by-step explanation:

A parallelogram is a figure of four sides, such that opposite sides are parallel

A rectangle is a four-sided figure such that all internal angles are 90°

Here, the statement is:

"A rectangle is sometimes a parallelogram but a parallelogram is always a

rectangle."

Here if we found a parallelogram that is not a rectangle, then that is enough to prove that the statement is false.

The counterexample is a rhombus, which is a parallelogram that has two internal angles smaller than 90° and two internal angles larger than 90°, then this parallelogram is not a rectangle, then the statement is false.

The correct statement would be:

"A parallelogram is sometimes a rectangle, but a rectangle is always a parallelogram"

6 0
3 years ago
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