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2 years ago

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Jenny randomly selects 20 boxes of crayons from the shelf and finds two boxes with at least one broken crayon. If the shelf hold

s 130 boxes, how many would you expect to have at least one broken crayon?

1 answer:

MArishka [77]2 years ago

3 0

13 crayons she would expect to be broken

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A spinner with 10 equally sized slices has 10 yellow slices. The dial is spun and stops on a slice at random. What is the probab

djverab [1.8K]

Answer:

1/10

Step-by-step explanation:

there are 10 slices, so if the probability of it landing on one of them is 1/10

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2 years ago

It takes 40 minutes for 8 people to paint 4 walls. How many minutes does it take 19people to paint 7 walls?

Slav-nsk [51]

Hey hey!

56 would be the answer.

WAIT, don’t leave just yet! You have to show at least some work! You CANT learn if you don’t know what you’re doing.

Here’s how I got the answer:

7:4 walls = 10:8 people =M:40 minutes
M = (7/4) / (10/8) x 40
M = 56 minutes.

If that helped let me know by hitting the thanks button or reply with any help you need.

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3 years ago

What's the system of linear equations by the solution graphed below

AfilCa [17]

D should be the correct answer. <span>Hope this helps! Brainliest would be appreciated!</span>

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3 years ago

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Compare 900 cm 9000 mm

dmitriy555 [2]

9000mm is equivalent to 900cm

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3 years ago

Recall the equation for a circle with center (h, k) and radius r. At what point in the first quadrant does the line with equatio

lina2011 [118]

Answer:

The point of intersection is:

$\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)$

Step-by-step explanation:

We want to find the point in QI at which the line with the equation:

$y=0.5x+5$

Intersect a circle with a radius of 3 and a center of (0, 5).

First, write the equation of a circle. The equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is (0, 5), <em>h</em> = 0 and <em>k</em> = 5. The radius is 3. So, <em>r</em> = 3. Substitute:

$(x-0)^2+(y-5)^2=(3)^2$

Simplify:

$x^2+(y-5)^2=9$

At the point where the two equations intersect, its <em>x-</em>coordinate and <em>y-</em>coordinate will be the same. Therefore, we can substitute the equation of the line into the equation of the circle and solve for <em>x</em>. So:

$x^2+((0.5x+5)-5)^2=9$

Simplify:

$x^2+(0.5x)^2=9$

Square:

$x^2+0.25x^2=9$

Combine like terms:

$\displaystyle 1.25x^2=\frac{5}{4}x^2=9$

Solve for <em>x: </em>

<em /> $\displaystyle \begin{aligned} x^2&=\frac{36}{5} \\ x&=\pm\sqrt{\frac{36}{5}} \\ x&\Rightarrow \frac{6}{\sqrt{5}}=\frac{6\sqrt{5}}{5}\approx2.68\end{aligned}$ <em />

Note that since we are looking for the point of intersection in QI, <em>x</em> should be positive. So, we can ignore the negative answer.

To find the <em>y-</em>coordinate, substitute the <em>x-</em>value back into either equation. Using the linear equation:

$\displaystyle y=0.5\left(\frac{6\sqrt{5}}{5}\right)+5=\frac{3\sqrt{5}}{5}+5\approx 6.34$

So, the point of intersection in QI is:

$\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)$

6 0

2 years ago