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Firlakuza [10]
3 years ago
9

Find the perimeter of the polygon with the given verticesG(2,4), H(2,-3), J(-2,-3), K(-2,4)

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0
I graphed these vertices myself in the attached photo, and it turned out to be a rectangle;  With the thought that you perhaps made a typo and meant rectangle instead of polygon I continued on and found the perimeter of the rectangle.  

The formula for finding the perimeter of a rectangle is P = 2(l+w).  

I counted the units of the long side (K & J) to get the length, which is 7.

Next, I counted the units between J & H to find the width which is 4.  Now we're ready to use the formula.  

First I will add the length plus the width, 7 + 4 = 11.  

Then I will multiply 2 x 11 to get a product of 22.  

P = 22.  :D 

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How to find the other endpoint with the given endpoint and midpoint?
prohojiy [21]
To find the other endpoint with a given endpoint and midpoint, you subtract the midpoint values from the endpoint, then with whatever the answer is, you subtract that from the midpoint.
6 0
3 years ago
Will upvote brainiest answer and add friend
Mashcka [7]

Answer:

68°

Step-by-step explanation:

ABD is a right angle and the measure of it is 90°

m<CBD + m<ABC = m<ABD

4x + 52° + 8x - 10 = 90° add like terms

12x + 42° = 90°

12x = 48°

x = 4

m<CBD is 4x + 52° replace x with 4

4×4 + 52 = 68°

8 0
3 years ago
Write a number or expression in each blank space to create true equations.
Rina8888 [55]

Answer:

7(3+5)=7(3)+7(5)\\15-10=5(3-2)

Step-by-step explanation:

Both expressions are examples of the <em>distributive property</em>, which basically says "if I have <em>this </em>many groups of some size and <em>that</em> many groups of the same size, I've got <em>this </em>+ <em>that</em> groups of that size altogether."

To give an example, if I've got <em>3 groups of 5 </em>and <em>2 groups of 5</em>, I've got 3 + 2 = <em>5 groups of 5 </em>in total. I've attached a visual from Math with Bad Drawings to illustrate this idea.

Mathematically, we'd capture that last example with the equation

5(3)+5(2)=5(3+2). We can also read that in reverse: 3 + 2 groups of 5 is the same as adding together 3 groups of 5 and 2 groups of 5; both directions get us 8 groups of 5. We can use this fact to rewrite the first expression like this: 7(3+5)=7(3)+7(5).

This idea extends to subtraction too: If we have 3 groups of 4 and we take away 1 group of 4, we'd expect to be left with 3 - 1 = 2 groups of 4, or in symbols: 4(3)-4(1)=4(3-1)=4(2). When we start with two numbers like 15 and 10, our first question should be if we can split them up into groups of the same size. Obviously, you could make 15 groups of 1 and 10 groups of 1, but 15 is also the same as <em>3 groups of 5</em> and 10 is the same as <em>2 groups of 5</em>. Using the distributive property, we could write this as 15-10=3(5)-2(5)=5(3-2), so we can say that 15-10=5(3-2).

4 0
3 years ago
Which event has a probability other than 3?
tensa zangetsu [6.8K]
The probability of compound events combines at least two simple events, either the union of two simple events or the intersection of two simple events.
6 0
2 years ago
Mt. McKinley, in Alaska, is the highest mountain in North America at 20,320
gladu [14]

Answer:

12700 feet

Step-by-step explanation:

Do 5/8 of 20,320

Do 20320 divided by 8 which is 2540

Do 2540 times 5 which is 12700

6 0
2 years ago
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