Find the perimeter of the polygon with the given verticesG(2,4), H(2,-3), J(-2,-3), K(-2,4)
1 answer:
I graphed these vertices myself in the attached photo, and it turned out to be a rectangle; With the thought that you perhaps made a typo and meant rectangle instead of polygon I continued on and found the perimeter of the rectangle.
The formula for finding the perimeter of a rectangle is P = 2(l+w).
I counted the units of the long side (K & J) to get the length, which is 7.
Next, I counted the units between J & H to find the width which is 4. Now we're ready to use the formula.
First I will add the length plus the width, 7 + 4 = 11.
Then I will multiply 2 x 11 to get a product of 22.
P = 22. :D
The formula for finding the perimeter of a rectangle is P = 2(l+w).
I counted the units of the long side (K & J) to get the length, which is 7.
Next, I counted the units between J & H to find the width which is 4. Now we're ready to use the formula.
First I will add the length plus the width, 7 + 4 = 11.
Then I will multiply 2 x 11 to get a product of 22.
P = 22. :D
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Answer:
Given: ABCD is a parallelogram.
Prove: Angle A and B are supplementary and C and D are supplementary.
That is, m∠A + m∠B = 180° and m∠C + m∠D = 180°
Statement Reason
1. ABCD is a parallelogram 1. Given
2.m∠A=m∠C and m∠B=m∠D 2. Definition of parallelogram.
3.m∠A+m∠B+m∠C+m∠D=360° 3. Definition of quadrilateral
4. m∠A+m∠B+m∠A+m∠B=360° 4. By substitution
⇒ 2( m∠A + m∠B ) = 360°
⇒ m∠A + m∠B = 180°
Similarly, m∠C + m∠D = 180°
5.∠A and ∠C are supplementary, 5. Def. of Supplementary
∠ B and ∠D are supplementary
