Find the perimeter of the polygon with the given verticesG(2,4), H(2,-3), J(-2,-3), K(-2,4)
1 answer:
I graphed these vertices myself in the attached photo, and it turned out to be a rectangle; With the thought that you perhaps made a typo and meant rectangle instead of polygon I continued on and found the perimeter of the rectangle.
The formula for finding the perimeter of a rectangle is P = 2(l+w).
I counted the units of the long side (K & J) to get the length, which is 7.
Next, I counted the units between J & H to find the width which is 4. Now we're ready to use the formula.
First I will add the length plus the width, 7 + 4 = 11.
Then I will multiply 2 x 11 to get a product of 22.
P = 22. :D
The formula for finding the perimeter of a rectangle is P = 2(l+w).
I counted the units of the long side (K & J) to get the length, which is 7.
Next, I counted the units between J & H to find the width which is 4. Now we're ready to use the formula.
First I will add the length plus the width, 7 + 4 = 11.
Then I will multiply 2 x 11 to get a product of 22.
P = 22. :D
You might be interested in
Answer:
Step-by-step explanation:
Notice when x increases 1, y is 4 times the previous one, so
the function is like
To determine the constant C, put any pair of (x, y)
Use x = 0, y = 0.2, so
0.2 = = C * 1 = C
then