Find the perimeter of the polygon with the given verticesG(2,4), H(2,-3), J(-2,-3), K(-2,4)
1 answer:
I graphed these vertices myself in the attached photo, and it turned out to be a rectangle; With the thought that you perhaps made a typo and meant rectangle instead of polygon I continued on and found the perimeter of the rectangle.
The formula for finding the perimeter of a rectangle is P = 2(l+w).
I counted the units of the long side (K & J) to get the length, which is 7.
Next, I counted the units between J & H to find the width which is 4. Now we're ready to use the formula.
First I will add the length plus the width, 7 + 4 = 11.
Then I will multiply 2 x 11 to get a product of 22.
P = 22. :D
The formula for finding the perimeter of a rectangle is P = 2(l+w).
I counted the units of the long side (K & J) to get the length, which is 7.
Next, I counted the units between J & H to find the width which is 4. Now we're ready to use the formula.
First I will add the length plus the width, 7 + 4 = 11.
Then I will multiply 2 x 11 to get a product of 22.
P = 22. :D
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Answer:
(2, 2 )
Step-by-step explanation:
Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
[ (x₁ + x₂ ) ,
(y₁ + y₂ ) ]
Here (x₁, y₁ ) = (A(5, 8) and (x₂, y₂ ) = B(- 1, - 4) , thus
midpoint = [ (5 - 1),
(8 - 4 ) ] = (2, 2 )