You just need to plug those expressions inside the formula: it doesn't matter if they're expressions involving a variable instead of plain numbers: the formula becomes

$V = \pi (x+8)^2(2x+3)$

If you want, you can simplify it by expanding the square and then multiply the two parenthesis:

$V = \pi (x^2+16x+64)(2x+3) = \pi (2 x^3 + 35 x^2 + 176 x + 192)$

6 0

3 years ago

In a certain fraction, the numerator is 4 less than the denominator. If 4 is added to both the numerator and the denominator , t

love history [14]

Answer:

Step-by-step explanation:

If the new fraction is 8/12 I will show how to find it.

Let's say the original denominator is x, then the numerator is x-4, so we have (x-4)/x.

Then it says f we add 4 to both, so now we have x/(x+4) this equals 8/12. Now, keep in mind -4 cannot be an answer because it would make x/(x+4) be divided by 0 which wouldn't exist.

Now we just use algebra.

x/(x+4) = 8/12

12x = 8(x+4)

12x = 8x + 32

4x = 32

x = 8

So the original fraction (x-4)/x = (8-4)/8 = 4/8

5 0

3 years ago