Area of the trapezoid:
![\frac{12.8 + 4.2}{2} (4.9) = 41.65 cm^2](https://tex.z-dn.net/?f=%20%5Cfrac%7B12.8%20%2B%204.2%7D%7B2%7D%20%284.9%29%20%3D%2041.65%20cm%5E2)
Area of the rectangle:
4.2 x 3.1 = 13.02 cm^2
Area of each quarter circle:
![\frac{ \pi (3.1)^{2} }{4} = 7.54 cm^2](https://tex.z-dn.net/?f=%20%20%5Cfrac%7B%20%5Cpi%20%20%283.1%29%5E%7B2%7D%20%7D%7B4%7D%20%3D%207.54%20cm%5E2)
We have two quarter circles:
7.54 + 7.54 = 15.08
41.65 + 13.02 + 15.08 = 69.75 cm^2
Answer:
Step-by-step explanation:
1.put your percent over a 100 so
125%/100 then put 60 over x
2.then cross multiply 100x60=6000
3.then divide 6000 by 125 which is percent
4.your answer is-48
Given:
Triangle LJK.
LJ = 89 in, LK = 28 in and m∠L = 42°
To find:
The length of missing side JK.
Solution:
LJ = k = 89
LK = j = 28
JK = l = ?
Using law of cosine:
![l^{2}=j^{2}+k^{2}-2 jk \cdot \cos L](https://tex.z-dn.net/?f=l%5E%7B2%7D%3Dj%5E%7B2%7D%2Bk%5E%7B2%7D-2%20jk%20%5Ccdot%20%5Ccos%20L)
Substitute the given values.
![l^{2}=28^{2}+89^{2}-2 \cdot 28 \cdot 89 \cdot \cos 42^\circ](https://tex.z-dn.net/?f=l%5E%7B2%7D%3D28%5E%7B2%7D%2B89%5E%7B2%7D-2%20%5Ccdot%2028%20%5Ccdot%2089%20%5Ccdot%20%5Ccos%2042%5E%5Ccirc)
![l^{2}=784+7921-4984 \cdot (0.7)](https://tex.z-dn.net/?f=l%5E%7B2%7D%3D784%2B7921-4984%20%5Ccdot%20%280.7%29)
![l^{2}=784+7921-4984 \cdot (0.7431)](https://tex.z-dn.net/?f=l%5E%7B2%7D%3D784%2B7921-4984%20%5Ccdot%20%280.7431%29)
![l^{2}=784+7921-3703.6](https://tex.z-dn.net/?f=l%5E%7B2%7D%3D784%2B7921-3703.6)
![l^{2}=5001.4](https://tex.z-dn.net/?f=l%5E%7B2%7D%3D5001.4)
Taking square root on both sides.
![l=70.7](https://tex.z-dn.net/?f=l%3D70.7)
The length of the missing side is 70.7 in.
1) 50x30
2) 2000+409
3) 500+800