What are the correct answers NEED ANSWER ASAP PLEASE

Mathematics

1 answer:

pentagon [3]3 years ago

4 0

Answer:

Step-by-step explanation:

4) A photograph costs $20, so the cost of x photographs is 20x.

Similarly, the cost of y prints is $25.

So the total cost is 20x+25y, and this has to be less than or equal to 400, so C.

5) just plug each pair in.

For example for the first option, x=5 and y=10, and since 20(5)+25(10)=100+250. which is less than or equal to 400, it works.

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A fruit company has 20% returns in periods of normal rainfall and -3% returns in droughts. The probability of normal rainfall is

WARRIOR [948]

Answer:

$E(x) = 10.8\% \\\\$

The fruit company’s expected returns are 10.8%

Step-by-step explanation:

The expected returns of the fruit company is given by

$E(x) =\sum (x \cdot P(x)) \\\\$

For the given case,

Returns in normal rainfall = x₁ = 20% = 0.20

Returns in drought = x₂ = -3% = -0.03

Probability of normal rainfall = P(x₁) = 60% = 0.60

Probability of drought = P(x₂) = 40% = 0.40

So, the expected value of returns is

$E(x) = x_1 \cdot P(x_1) + x_2 \cdot P(x_2) \\\\E(x) = 0.20 \cdot 0.60 - 0.03 \cdot 0.40 \\\\E(x) = 0.12 - 0.012 \\\\E(x) = 0.108 \\\\E(x) = 10.8\% \\\\$

Therefore, the fruit company’s expected returns are 10.8%

7 0

3 years ago

Will give brainliest, please help fast

Gekata [30.6K]

Answer:

Converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

Step-by-step explanation:

we are given quadratic equation: $x^2-20x+13=0$

And we need to convert it into completing the square method.

Completing the square method is of form: $a^2-2ab+b^2=(a-b)^2$

Looking at the given equation $x^2-20x+13=0$

We have a = x

then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20

So, 20x in form of 2ab can be written as: 2(x)(10)

So, we need to add and subtract (10)^2 on both sides

$x^2-20x+13=0\\x^2-2(x)(10)+(10)^2-(10)^2+13=0\\(x^2-2(x)(10)+(10)^2) \:can\: be\: written\: as\: (x-10)^2 \\(x-10)^2-100+13=0\\(x-10)^2-87=0\\(x-10)^2=87$