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3 years ago

Name a number that can be evenly divided by 6 and and by 7

1 answer:

7 0

There are an infinite number of them. The smallest one is 42,
and every multiple of 42 is another one.

I don't remember the official correct way to solve this problem.
I can only show you my own way of doing it.

I take the bigger number, and I go through its multiples, one by one,
until I spot one that's also a multiple of the smaller one.

Example: 6 and 7.
Go through the multiples of 7:

7 ... no, not a multiple of 6
14 ... no, not a multiple of 6
21 ... no, not a multiple of 6
28 ... no, not a multiple of 6
35 ... no, not a multiple of 6
42 ... Yes ! A multiple of 6. yay !

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How can you determine which property of equality is needed to isolate a variable and solve a given equation? Explain. A. Use inv

mamaluj [8]

Answer:

A. Use inverse relationships to "undo" the operation.

Step-by-step explanation:

I took the , and this was the correct answer. :)

6 0

3 years ago

Read 2 more answers

A special type of door lock has a panel with five buttons labeled with the digits 1 through 5. This lock is opened by a sequence

belka [17]

There are several ways the door can be locked, these ways illustrate combination.

There are 3375 possible combinations

From the question, we have:

$\mathbf{n = 5}$ --- the number of digits

$\mathbf{r = 3}$ ---- the number of actions

Each of the three actions can either be:

Pressing one button
Pressing a pair of buttons

The number of ways of pressing a button is:

$\mathbf{n_1 = ^5C_1}$

Apply combination formula

$\mathbf{n_1 = \frac{5!}{(5-1)!1!}}$

$\mathbf{n_1 = \frac{5!}{4!1!}}$

$\mathbf{n_1 = \frac{5 \times 4!}{4! \times 1}}$

$\mathbf{n_1 = 5}$

The number of ways of pressing a pair is:

$\mathbf{n_2 = ^5C_2}$

Apply combination formula

$\mathbf{n_2 = \frac{5!}{(5-2)!2!}}$

$\mathbf{n_2 = \frac{5!}{3!2!}}$

$\mathbf{n_2 = \frac{5 \times 4 \times 3!}{3! \times 2 \times 1}}$

$\mathbf{n_2 = 10}$

So, the number of ways of performing one action is:

$\mathbf{n =n_1 + n_2}$

$\mathbf{n =5 + 10}$

$\mathbf{n =15}$

For the three actions, the number of ways is:

$\mathbf{Action = n^3}$

$\mathbf{Action = 15^3}$

$\mathbf{Action = 3375}$

Hence, there are 3375 possible combinations

Read more about permutation and combination at:

brainly.com/question/4546043

4 0

3 years ago

Help me please that’s easy but....

grin007 [14]

Let's resolve the powers of 10 to make them comparable

47000

45000

5000

280000

125000

Now you can see the largest is 280000 and the smallest is 5000

Their difference is 280000 - 5000 = 275000

4 0

3 years ago

Evaluate 6(-3) -1-51+131= O 16 -10 -20

oee [108]

Answer:

-20

Step-by-step explanation:

6(-3) - |-5| + |3|

First multiply

-18 - |-5| + |3|

Then take the absolute values

-18 - 5 + 3

Subtract

-23 +3

Add

-20

4 0

2 years ago

Read 2 more answers

What is the area of a sector with a central angle of 210 degrees and a diameter of 4.6m?

WINSTONCH [101]

Sector area = (central angle / 360) * PI * radius^2
sector area = (210 / 360) * PI * 2.3^2
sector area = (7 / 12) * PI * 5.29
sector area = 9.6944313302 
sector area = 9.7 square meters (rounded)

Source:
http://www.1728.org/radians.htm

8 0

3 years ago