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lawyer [7]
2 years ago
8

HELP ME ASAP a is the blue line. B is the purple line. C is the orange line. And D is the green line

Mathematics
2 answers:
JulijaS [17]2 years ago
6 0

Answer: D (Green)

Step-by-step explanation:

a_sh-v [17]2 years ago
5 0

Answer:

Step-by-step explanation:

There should be three others

<DPB

<APC

And the acute angle at D going up and to the right. It's not lettered so I can give it as an answer. I have no idea what the colors mean.

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Estimated about $224.00
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Please explain me how to solve it <br> cos2x+cos4x ≥0
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Does this help at all?

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You are doing a case study of the death of John F Kennedy. You employ many data collection methods in
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Answer:

B. Of the people surveyed that were alive at the time, 90% of them knew exactly where they were when they heard the news.

Step-by-step explanation:

4 0
2 years ago
(6-3(cube root of 6)/(cube root of 9)
MatroZZZ [7]

For this case we must simplify the following expression:

\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}

Multiplying the numerator and denominator by(\sqrt [3] {9}) ^ 2

\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =

We rewrite:

\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =

By properties of powers we have that:

a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =

We rewrite, moving the exponent within the radical:

\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =

We can rewrite3 * 3 ^ 3 = 81

\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =

We simplify:

\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =

We apply distributive property:

\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =

Simplifying we finally have:

2 \sqrt [3] {3} - \sqrt [3] {18}

Answer:

2 \sqrt [3] {3} - \sqrt [3] {18}

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3 years ago
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Answer:

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