2 years ago

Find the Nonpermissible replacement for x in this expression 1/-8x

Mathematics

1 answer:

beks73 [17]2 years ago

4 0

The expression is Undefined for x=0, assuming you intend 1/(-8x).

x=0 is "nonpermissible"

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Step-by-step explanation:

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we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$