You can write 2311 and 3912 in the form
:


Then


Taken modulo 20, the terms containing powers of 20 vanish and you're left with

We further have

so we end up with

and so
.
###
If instead you're trying to find
, you can apply Euler's theorem. We can show that
using the Euclidean algorithm. Then since
, and 8 divides 3912, we have

To show 2311 and 20 are coprime:
2311 = 115*20 + 11
20 = 1*11 + 9
11 = 1*9 + 2
9 = 4*2 + 1 => gcd(2311, 20) = 1
Answer:
Constant of porportionality is 4
Step-by-step explanation:
Directly proportional
y = kx
For x = 2, y = 8
8 = 2(k)
Divide both sides by 2
4 = k
Answer:
The use of sampling would be best in the following situation:
a. The need for precise information is less important.
Step-by-step explanation:
Sampling:
It is such a process of analysis in which we divide a large proportion of data into smaller proportions called samples to determine the characteristics of that data.
- The option a is correct as in sampling, we take a smaller proportion from a large pool of data so when the precise information is less important, it is a good way to use sampling.
- The option b is not correct as the number of items comprising the population is always large.
- The option c is not correct as the likelihood of selecting a representative is relatively not small rather it is large.
- The option d is incorrect as the use of sampling is not appropriate in all of these situations.