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2 years ago

6^2n×15^n×10^2n-3/6^2m×15^m-n×10^3

Mathematics

1 answer:

Hitman42 [59]2 years ago

4 0

6^2n*15^n*10^2n-3/6^2m*15^m-n*10^3
3600n*15^n-3/6^2*15^m-n*10^3
3600n*15^n-3/36*15^m-n*1000
3600n*15^n-3/36*15^m-1000n

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snow_lady [41]

Answer:

Average velocity of the function over the given interval

= $log(\frac{7}{4} ) -2$

Step-by-step explanation:

Explanation:-

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

Average velocity = $\frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx$

= $\frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx$

now integrating

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= $\frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}$

= $\frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))$

by using formulas

log a-log b = log(a/b)

on simplification , we get

= $\frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)$

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Average velocity of the function over the given interval

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Answer: -7/3≤t≤5/3

Step-by-step explanation:

|2t + 2/3|≤4

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(2t + 2/3≤4)*3

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6t≤10

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(2t + 2/3>=-4)*3

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2 years ago

6^2n×15^n×10^2n-3/6^2m×15^m-n×10^3​

6^2n×15^n×10^2n-3/6^2m×15^m-n×10^3