Find an equation of the tangent line to the curve at the given point.y = 7x2 − x3, (1, 6)y = Correct: Your answer is correct. Il
lustrate by graphing the curve and the tangent line on the same screen.
1 answer:
Answer:
y = 11(x -1) +6
Step-by-step explanation:
The slope at the given point is ...
y' = 14x -3x^2 = 14(1) -3(1^2) = 11
Then the point-slope equation for the line can be written as ...
y = m(x -h) +k . . . . . . for slope m at point (h, k)
y = 11(x -1) +6
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