Answer:
I don't understand it.....
0.36 J of work is done in stretching the spring from 15 cm to 18 cm.
To find the correct answer, we need to know about the work done to strech a string.
<h3>What is the work required to strech a string?</h3>
- Mathematically, the work done to strech a string is given as 1/2 ×K×x².
- K is the spring constant.
<h3>What will be the spring constant, if 40N force is required to hold a 10 cm to 15 cm streched spring?</h3>
- The force experienced by a streched spring is given as Kx. x is the length of the spring streched from its natural length.
- Then K = Force / x.
- Here x = 15 - 10 = 5 cm = 0.05 m
- K = 40/0.05 = 800N/m.
<h3>What will be the work required to strech that spring from 15 cm to 18 cm?</h3>
- Work done = 1/2×k×x²
- Here x= 18-15=3cm or 0.03 m
- So, W= 1/2×800×0.03² = 0.36 J.
Thus, we can conclude that the work done is 0.36 J.
Learn more about the spring force here:
brainly.com/question/14970750
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Answer:
Explanation:
The picture attached shows the full explanation and i hope it helps. Thank you
They start at 1 meter and after 10 seconds they've moved to 6 meters.
6 - 1 = 5 meters
Answer:
B) 3.33 m/s²
Explanation:
Given that,
The initial velocity of Juan, u = 10 m/s
Final velocity of Juan, v = 60 m/s
Time taken, t = 15 s
The acceleration is given by the relation
a = v-u/t m/s²
Substituting in the above equation
a = 60 - 10 / 15
a = 3.33 m/s²
Hence, the acceleration of the Juan is, a = 3.33 m/s²
