Question

In an experiment, a shearwater (a seabird) was taken from its nest, flown a distance 5190 km away, and released. It found its way back to its nest 15.0 days after release. If we place the origin in the nest and extend the +x-axis to the release point, what was the bird's average velocity for the return flight?

Answer 1

Answer:

The bird's average velocity is 4.00 m/s.

Explanation:

Given that,

Distance = 5190 km

Time$t = 15.0\ days = 1.296\times10^{6}\ sec$

We need to calculate the bird's average velocity for the return flight

Using formula of average velocity

$v_{avg}=\dfrac{d_{i}-d_{f}}{t}$

Where, d = position

t = total time

Put the value into the formula

$v_{avg}=\dfrac{0-5190\times10^{3}}{1.296\times10^{6}}$

$v_{avg}=-4.00\ m/s$

Negative sign shows the bird is traveling in negative x -axis.

Hence, The bird's average velocity is 4.00 m/s.