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rewona [7]
3 years ago
5

If a person weighs 717 N on earth and 5320 N on the surface due to gravity on that planet? of a nearby planet, what is the accel

eration
a. 83.6

b. 72.7

c. 63.2

d. 53.1
Physics
2 answers:
mash [69]3 years ago
8 0

Answer:

g'=72.7\ m/s^2

Explanation:

It is given that,

Weight of the person on Earth, W = 717 N

Weight of a person is given by the following formula as :

W=mg

g is the acceleration due to gravity on earth

m=\dfrac{W}{g}

m=\dfrac{717\ N}{9.81\ m/s^2}

m = 73.08 kg

The mass of an object is the amount of matter contained in it. It is same everywhere.

Let W' is the weight of the person on the surface of a nearby planet, W' = 5320 N

g' is the acceleration due to gravity on that planet. So,

g'=\dfrac{W'}{m}

g'=\dfrac{5320\ N}{73.08\ kg}                

g'=72.79\ m/s^2

or

g'=72.7\ m/s^2

So, the acceleration due to gravity on that planet is 72.79\ m/s^2. So, the correct option is (b). Hence, this is the required solution.     

Studentka2010 [4]3 years ago
4 0

The answer is B. You divide 717 by the acceleration by gravity of earth (9.8 m/s) and divide 5320 by your answer.

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