Question

If a person weighs 717 N on earth and 5320 N on the surface due to gravity on that planet? of a nearby planet, what is the acceleration
a. 83.6

b. 72.7

c. 63.2

d. 53.1

Answer 1

Answer:

$g'=72.7\ m/s^2$

Explanation:

It is given that,

Weight of the person on Earth, W = 717 N

Weight of a person is given by the following formula as :

$W=mg$

g is the acceleration due to gravity on earth

$m=\dfrac{W}{g}$

$m=\dfrac{717\ N}{9.81\ m/s^2}$

m = 73.08 kg

The mass of an object is the amount of matter contained in it. It is same everywhere.

Let W' is the weight of the person on the surface of a nearby planet, W' = 5320 N

g' is the acceleration due to gravity on that planet. So,

$g'=\dfrac{W'}{m}$

$g'=\dfrac{5320\ N}{73.08\ kg}$                

$g'=72.79\ m/s^2$

or

$g'=72.7\ m/s^2$

So, the acceleration due to gravity on that planet is $72.79\ m/s^2$. So, the correct option is (b). Hence, this is the required solution.     

Answer 2

The answer is B. You divide 717 by the acceleration by gravity of earth (9.8 m/s) and divide 5320 by your answer.