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maxonik [38]
2 years ago
7

Select all triangles whose side lengths prove they are right triangles. You must select all that apply.

Mathematics
2 answers:
d1i1m1o1n [39]2 years ago
7 0

Answer:

B and D

Step-by-step explanation:

0.5 squared + 1.2 squared = 1.69  \sqrt{}1.69 = 1.3

3 squared plus 4 squared = 25 \sqrt{}25 = 5

if you need help with a question similar to this, you can use Desmos Calculator. hopes this helps :)

Bogdan [553]2 years ago
6 0
It is D.

Reason. 3^2 is 9, 4^2 is 16.
16+9= 25
The square root of 25 is 5.
Therefore it is D.
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Which expression is equivalent to this polynomial? 6x2 + 10x − 56=
hammer [34]
2nd one maybe I’m not to sure srry
4 0
3 years ago
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Which digit is in the hundreds place in 3,254,107
ozzi
The 1 is in the hundreds place good luck!!!
5 0
3 years ago
Solve the equation, <br>-3|6n-2|+5=8
Marianna [84]
Hey..... Nice to see you :)
Let me help you out.

-3|6n -2| + 5 = 8
-3|6n -2| = 8-5
-3|6n -2| = 3
|6n -2| = 3/-3
|6n -2| = -1
Now, solve absolute value
No solutions.

Because absolute value cannot be less than 0.


I hope that's help !
5 0
3 years ago
Need help ASAP !!! And show work please
sammy [17]

Answer:

\sqrt{40} or 6.32

Step-by-step explanation:

We can find the distance between two points by using this formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

where the x and y values are derived from the given points

The points given are ( -2 , 5 ) and ( 4 , 3 )

So we plug in the x and y values of those coordinates into the distance formula

\sqrt{(4-(-2)^2+(3-5)^2} \\4-(-2)=6\\3-5=-2\\d=\sqrt{6^2+-2^2} \\6^2=36\\-2^2=4\\36+4=40\\d=\sqrt{40}

or 6.32

6 0
3 years ago
Find m∠MON<br> I have a hard time with theses
fredd [130]

Answer:

m∠MON = 15°

Step-by-step explanation:

The given parameters are;

m∠LON = 77°

m∠LOM = 9·x + 44°

m∠MON = 6·x + 3°

By angle addition postulate, we have;

m∠LON = m∠LOM + m∠MON

Therefore, by substituting the known values, we have;

∴ 77° = 9·x + 44° + 6·x + 3°

77° = 9·x + 44° + 6·x + 3° = 15·x + 47°

77° = 15·x + 47°

77° - 47° = 15·x

15·x = 77° - 47° = 30°

15·x = 30°

x = 30°/15 = 2°

x = 2°

Given that m∠MON = 6·x + 3° and x = 2°, we have;

m∠MON = 6 × 2° + 3° = 12° + 3° = 15°

m∠MON = 15°.

3 0
3 years ago
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