2 years ago

Work out m and c for the line: y − 3 x = 5

Mathematics

1 answer:

ludmilkaskok [199]2 years ago

8 0

Answer:

Step-by-step explanation:

Write the equation in slope intercept form.

y = mx +c

y - 3x = 5

y = 3x + 5

m = 3 and c = 5

You might be interested in

DONT ANSWER IF YOU SEND LINKS OR NOT CORRECT ANSWERS

marta [7]

What form of math is this?

4 0

3 years ago

Show three ways to write the expression 5 times x algebraically.

Dahasolnce [82]

Step-by-step explanation:

1st way: 5x

2nd way: 5.x

third way: 5(x)

4 0

2 years ago

Read 2 more answers

Please help, only two answers

Illusion [34]

Answer:

What I think are the answers are C,D, and A, hope this helps.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

4 0

3 years ago

Helppp mehh plzz..............

soldier1979 [14.2K]

Answer:

i think it A

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers