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pochemuha
3 years ago
8

C^4 ____ c^3 please could you help

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Hello.

Remember the Property of exponents:

\mathrm{\displaystyle\frac{a^{m} }{a^{n} } =a^{m-n}}

Let's use it to solve our maths problem.

\mathrm{\displaystyle\frac{c^{4} }{c^{3} } =c^{4-3} }

Subtract the exponents:

\mathrm{c^{1} =c}

Therefore, the answer is

c.

I hope it helps.

Have a nice day.

\boxed{imperturbability}

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tatiyna
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please vote my answer brainliest. thanks!
6 0
3 years ago
Select the correct answer.
Finger [1]

Answer:

(c)\ f(5) < g(3)

Step-by-step explanation:

Given

f(n) = 2(n-1) -1

g(n) = 3n + 6

Required

Which is correct

(a)\ g(6) < f(6)

Calculate g(6) and f(6)

f(n) = 2(n-1) -1

f(6) = 2(6 - 1) -1 = 2*5-1=9

g(n) = 3n + 6

g(6) =3*6 +6 =24

<em>(a) is false, because g(6) > f(6) i.e. 24 > 9</em>

<em></em>

(b)\ f(7) > g(10)

Calculate f(7) and g(10)

f(n) = 2(n-1) -1

f(7) = 2*(7-1)-1=2*6-1=11

g(n) = 3n + 6

g(10) =3*10+6=36

<em>(b) is false, because f(7) < g(10) i.e. 11 <36</em>

<em></em>

(c)\ f(5) < g(3)

Calculate f(5) and g(3)

f(n) = 2(n-1) -1

f(5) =2 *(5-1)-1 = 2*4-1=7

g(n) = 3n + 6

g(3) = 3*3+6=9+6=15

<em>(c) is true, because f(5) < g(3) i.e. 7 <15</em>

5 0
3 years ago
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